I am trying to write a function which returns a value 1 if the number entered is a power of two, else it returns a value 0.
function val = func_1(num)
while not(num == 1)
if num%2~=0
val=0;
break
end
num=num/2;
val=1;
end
end
But unfortunately, the function always return a value 1. Is there any error in the algorithm or the code? Thanks in advance for any help.
In Matlab, % is the comment character. Everything from that point onwards until the end of the line is ignored. This means that this line if num%2~=0 is not doing what you think it does.
Instead, use the mod function. link. In this case, the line in question becomes if mod(num, 2)~=0.
On a separate note, I suspect there is a much more efficient way of doing this. See, for example, here.
%.In Matlab, for any integer num:
val=(num~=0 & (bitand(num,num-1)==0));
num==2^nextpow2(num)