Counting executions of batch script

Question

I need to count, in a file, the number of times a batch script has been executed.

In linux shell, this would be something like

counter=`cat buildnumber.txt`;
counter=`echo $counter+1|bc`
echo $counter > buildnumber.txt

but how does one do this in a batch file?

Dunno whether there is a less overkill-y calculator available in bash... — Alexander
– Alexander, Commented Sep 9, 2016 at 12:23
yes, why not? Math Commands unix.stackexchange.com/q/40786/44425 stackoverflow.com/q/1088098/995714 — phuclv
– phuclv, Commented Sep 9, 2016 at 13:19

Stephan · Accepted Answer · 2016-09-09 06:43:43Z

3

exactly the same logic, but using batch commands:

<buildnumber.txt set /p counter=
set /a counter +=1
echo %counter%>buildnumber.txt

answered Sep 9, 2016 at 6:43

Stephan

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2 Comments

geisterfurz007 Over a year ago

Is it really <buildnumber.txt and then set? Looks a bit screwed up... Just curious.

Stephan Over a year ago

@geisterfurz007 it doesn't matter where you put the redirection. set /p counter= <buildnumber.txt works exactly the same. (run with echo on to see, that the parser interprets both possibilities the same way)

Hackoo · Accepted Answer · 2016-09-09 10:37:11Z

1

This is my approch to count the number of execution for the batch script :

@echo off
Setlocal enabledelayedexpansion
Title Count the number of times my BATCH file is run
Mode Con Cols=60 lines=3 & color 0E
set /a count=1
set "FileCount=%tmp%\%~n0.txt"
If Not exist "%FileCount%" (
    echo !count! > "%FileCount%"
) else (
    For /F "tokens=*" %%a in ('Type "%FileCount%"') Do (
        set /a count=!count! + %%a
        echo !count! > "%FileCount%"
    )
)
echo.
echo        This batch script is running for "!count! time(s)"
EndLocal
pause>nul

edited Sep 9, 2016 at 10:37

answered Sep 9, 2016 at 10:32

Hackoo

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