matching pattern with regular expression in python

Question

I have written a pattern to match typedef followed by any number of characters until it matches the 1st opening braces followed by a * , then a word , closing braces and so on. the pattern is

pattern_funp = re.compile(r"typedef(.*?)\(\*(\w+)\s*\)\s*\(.*?\)\s*")

The above pattern matches acpi_adr_space_setup in the line below which is correct:

typedef acpi_status(*acpi_adr_space_setup) (acpi_handle region_handle,u32 function,void *handler_context,  void **region_context);

but in the below line it matches func which is not what i want:

typedef void *call_rcu_func_t (struct rcu_head *head,void (*func1)(struct rcu_head *head));

The pattern should match the 1st ( followed by * not the 2nd (with *.

Then what you want to match in the 2nd example?

Quinn
– Quinn

2016-03-31 13:33:40 +00:00
Commented Mar 31, 2016 at 13:33 — Quinn
– Quinn, Commented Mar 31, 2016 at 13:33
the regex should not match the 2nd example.

Anusha HV
– Anusha HV

2016-04-01 05:27:55 +00:00
Commented Apr 1, 2016 at 5:27 — Anusha HV
– Anusha HV, Commented Apr 1, 2016 at 5:27

Me1234567 · Accepted Answer · 2016-03-31 11:49:10Z

2

Not sure getting what you mean, but if you want not to match anything after the 1st parenthesis, putting [^(] instead of . should do the trick:

pattern_funp = re.compile(r"typedef([^(]*?)\(\*(\w+)\s*\)\s*\(.*?\)\s*")

answered Mar 31, 2016 at 11:49

Me1234567

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