My background is .net, I'm fairly new to Java. I'm doing some work for our company's java team and the architect needs me to implement a method that takes an InputStream (java.io) object. In order to fulfill the method's purpose I need to convert that into a byte array. Is there an easy way to do this?
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Be aware that this may be memory hogging.BalusC– BalusC2010-01-29 17:18:27 +00:00Commented Jan 29, 2010 at 17:18
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2 Answers
The simplest way is to create a new ByteArrayOutputStream, copy the bytes to that, and then call toByteArray:
public static byte[] readFully(InputStream input) throws IOException
{
byte[] buffer = new byte[8192];
int bytesRead;
ByteArrayOutputStream output = new ByteArrayOutputStream();
while ((bytesRead = input.read(buffer)) != -1)
{
output.write(buffer, 0, bytesRead);
}
return output.toByteArray();
}
2 Comments
quikchange
Make sure you flush the outputstream before returning.
Jon Skeet
@quikchange: There's no need when you're using a ByteArrayOutputStream - where would it buffer to?
A simple way would be to use org.apache.commons.io.IOUtils.toByteArray( inputStream ), see apache commons io.
