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Can I use feedparser.parse to parse a rsshub feed(https://github.com/DIYgod/RSSHub) or some other way?Such as I want to get rss content of "https://rsshub.app/bilibili/ranking/0/3/1". And I can open it in folo(https://github.com/RSSNext/Folo?tab=readme-ov-file), but now I want to parse it in codes, so I use feedparser.parse("https://rsshub.app/bilibili/ranking/0/3/1") to deal with it. But I always get errors like SAXParseException('undefined entity').So what is the right way. Could give a complete, executable function?

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    can you do print(requests.get("https://rsshub.app/bilibili/ranking/0/3/1"))? Commented Nov 18 at 16:00
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