Oracle: how to filter for the partial date from any string appear in the column? [closed]

I have a case where I need to filter for the partial date string from a column.

Here is the input:

date_value
-----------------------------
7-03 start 4444
03/2022 follow up
1111 7-03 03/2022 something
kk 03-2021 test 3333
follow up 15/12 note
7-03 start 3333
03/2022 follow up
1111 7-03 03/2022 something
kk 03-2021 test 3333
follow up 15/12 note
14-2627272 15/01

This is the code I tried, but I'm wondering how I can handle any exceptional case where partial date may appear in any format:

SELECT date_value
FROM notes_test r
WHERE EXISTS (SELECT 1
              FROM (SELECT REGEXP_SUBSTR(r.date_value, '[^ ]+', 1, LEVEL) AS token
                    FROM dual
                    CONNECT BY LEVEL <= LENGTH(r.date_value) - LENGTH(REPLACE(r.date_value, ' ', '')) + 1) t
              WHERE REGEXP_COUNT(t.token, '[/-]') = 1
                AND (REGEXP_LIKE(t.token, '^([0-2]?[0-9]|3[01])/(0?[1-9]|1[0-2])$')  
                     OR REGEXP_LIKE(t.token, '^([0-2]?[0-9]|3[01])-(0?[1-9]|1[0-2])$') 
                     OR REGEXP_LIKE(t.token, '^(0?[1-9]|1[0-2])/([0-9]{2,4})$')         
                     OR REGEXP_LIKE(t.token, '^(0?[1-9]|1[0-2])-([0-9]{2,4})$')        ) 
             )