Azure Function App -Calling a function in another file from function_app.py

Question

Very simply! I have a function app - function_app.py, trigger.py and init.py in the root

Its my first Azure Function App. if i run the two files separately, function_app.py, trigger.py, they both return the results. Trigger.py looks at a file on sharepoint and does some cleansing and reposts it back to sharepoint.

Trigger.py has a function called Trigger() and within that, the function connects to Sharepoint, looks at a file, then does some changes and then uploads it again. This does 100% work.

The problem lies with when i call it from the Function_App.py as I want to deploy this as a Azure Function App.

i've created a trigger. Runs fine; on deployment, it times out. When I debug, it gives the following

Found Python version 3.11.9 (py).

Azure Functions Core Tools
Core Tools Version:       4.0.7030 Commit hash: N/A +bb4c949899cd5659d6bfe8b92cc923453a2e8f88 (64-bit)
Function Runtime Version: 4.1037.0.23568

[2025-04-24T17:18:19.054Z] Requesting metadata from worker failed.
[2025-04-24T17:18:19.057Z] Microsoft.Azure.WebJobs.Script.Grpc: The operation has timed out.

The function_app looks like below:

import azure.functions as func
import logging
import json
from azure.functions import HttpRequest, HttpResponse
from  myFile import Trigger
    app = func.FunctionApp()
    @app.function_name(name="Trigger")
    @app.route(route="myApp", auth_level=func.AuthLevel.ANONYMOUS)
    def mytrigger(req: func.HttpRequest) -> func.HttpResponse:
        try:
            # Call the Trigger function
            Trigger()  # This runs the entire process you defined
            # Return a success message
            return func.HttpResponse(" process completed successfully.", status_code=200)
        except Exception as e:
            logging.error(f"Error executing  process: {str(e)}")
            return func.HttpResponse(f"An error occurred: {str(e)}", status_code=500)

If I don't import the file or call Trigger(), the function_app.py runs as normal and opens up the URL with the response. So, I don't understand why calling this within, is causing heartache.

The files are in the root of Project. I don't have them spread in different folders. Please someone tell me why something so simple is not working.

Move the heavy logic in Trigger() to a separate queue-triggered function to avoid timeout in your HTTP-triggered Azure Function. — Dasari Kamali
– Dasari Kamali, Commented Apr 25 at 3:33
Can you share your trigger.py and init.py codes in the question? — Dasari Kamali
– Dasari Kamali, Commented Apr 25 at 3:44
@Dave Ensure proper async handling in the Trigger() function to prevent blocking during SharePoint operations. Provide your code will try from my end. — Dasari Kamali
– Dasari Kamali, Commented Apr 25 at 10:29
@DasariKamali i figured it out. I needed a folder that was the same name as the decorator and place those files in that folder of the same name. — Dave
– Dave, Commented Apr 29 at 9:10

Dave · Accepted Answer · 2025-04-29 09:20:06Z

-1

The decorator had a function name explicitly named Trigger.

I needed to create a folder in Azure Function App called Trigger and place my files inside this folder. I originally had them in the root.

Issue resolved on moving files into Trigger folder.

answered Apr 29 at 9:20

Dave

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