How to get current function object in Python?

Question

Is there a way to get the current function I'm in?

I'm looking for the actual function object, not the function name.

    def foo(x,y):
        foo_again = <GET_CURRENT_FUNCTION>
        if foo_again == foo:
            print ("YES they are equal!")

I assume I could do that in Python inspect module, but I can't seem to find it.

EDIT The reason I want that is I want to print out the arguments to my function. And I can do that with inspect. Like this

   def func(x,y):
       for a in inspect.getfullargspec(func).args:
           print (a, locals()[a])

This works, but I don't want to have to manually write the function name. Instead, I want to do

   def func(x,y):
       for a in inspect.getfullargspec(<GET_CURRENT_FUNCTION>).args:
           print (a, locals()[a])

i plan to copy and paste these 2 lines of code to all functions that i want to see arguments for. so i don't want to change the function name every time i need to do it. — user3240688
– user3240688, Commented Sep 10, 2020 at 4:09

aerijman · Accepted Answer · 2020-09-10 02:15:08Z

1

from inspect.stack you can get the function's name.

Here is a workaround that might not be optimal but it gives your expected results.

def foo(x,y): 
    this_function = inspect.stack()[0].function 
    for a in inspect.getfullargspec( eval(this_function) ).args: 
        print(a, locals()[a]) 
    print(this_function)

Then

foo('a','b')
>>>
    x a
    y b
    foo

answered Sep 10, 2020 at 2:15

aerijman

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Daniel Walker · Accepted Answer · 2020-09-10 01:26:35Z

0

One way to accomplish this is by using a decorator. Here's an example:

def passFunction(func):
    @functools.wraps(func)
    def new_func(*args, **kwargs):
        return func(func,*args, **kwarsgs)
    return new_func

@passFunction
def foo(f, x, y):
    ...

foo(x,y)

answered Sep 10, 2020 at 1:26

Daniel Walker

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