How to get only certain values from an array?

Question

module.exports.getAll = async function (req, res) {
    try {
        const cards = await Card.find({})
        res.status(200).json(cards)
    } catch (e) {
        errorHandler(res, e)
    }
}

I am currently displaying an array in this form:

[
    {
        "ncard": "123123",
        "name": "sdf",
        "lim": "0",
        "ost": "0",
        "message": " ",
        "status": "1",
        "_id": "5f030111f5df83755eb65721",
        "date": "2020-07-06T10:46:41.001Z",
        "__v": 0
    },
...
]

But I want to receive in this form:

   [
        {
            "ncard": "123123",
            "name": "sdf",
            "_id": "5f030111f5df83755eb65721",
            "date": "2020-07-06T10:46:41.001Z",
            "__v": 0
        },
    ...
    ]

How can I do that?

Does this answer your question? mongo .find return specific field only for all user — ggorlen
– ggorlen, Commented Jul 21, 2020 at 4:36

vishnusaran · Accepted Answer · 2020-07-21 04:40:09Z

1

try this line

  module.exports.getAll = async function (req, res) {
        try {
            const cards = await Card.find({}).project({ ncard: 1, name: 1, date: 1})
            res.status(200).json(cards)
        } catch (e) {
            errorHandler(res, e)
        }
    }

answered Jul 21, 2020 at 4:40

vishnusaran

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Comments

SatishSharma445 · Accepted Answer · 2020-07-28 09:37:37Z

-1

you can try this.
await Card.find({}).project({ ncard: 1, name: 1, date: 1})

edited Jul 28, 2020 at 9:37

answered Jul 21, 2020 at 8:54

SatishSharma445

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