how to open the file with path name?

Question

I am trying to open the file using a path instead of file name I used glob.glob option to go and search in the path for an input file. Now I got struck with opening that. Any help would be appreciated.

import glob
a = (glob.glob("*/file.txt"))
with open (a, 'r') as f:

Trying to read the file.txt and I am getting error in line3. Any help would be appreciated.

Error: TypeError: expacted str, bytes or os.PathLike object, not list

James · Accepted Answer · 2020-07-20 20:15:27Z

1

glob.glob returns a list of file paths. You will need to access one of the paths in the list, or iterate over them.

import glob

a = glob.glob("*/file.txt")
with open(a[0], 'r') as f:
    text= f.read()

answered Jul 20, 2020 at 20:15

James

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3 Comments

user7090 Over a year ago

It is still giving me error saying : (result, consumed) = sel._buffer_decode(data, self.error, final) UnicodeDecodeError: 'utf - 8' code can't decode byte 0x8b in position 1: invalid start byte.

alani Over a year ago

@user7090 Sounds like you might need to open the file as binary format ('rb' instead of 'r').

user7090 Over a year ago

@alaniwi Is it possible to open the file in read format instead of reading in binary format

Barmar · Accepted Answer · 2020-07-20 20:15:25Z

0

glob.glob() returns a list. You need to loop through it, opening each file.

import glob

for filename in glob.glob("*/file.txt"):
    with open(filename, "r") as f:
        ...

answered Jul 20, 2020 at 20:15

Barmar

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10 Comments

user7090 Over a year ago

I am facing the same error as mentioned in the above comment

Barmar Over a year ago

That's completely unrelated. It's not a plain text file.

Barmar Over a year ago

Or you need to specify the encoding

user7090 Over a year ago

Will it read the data in the file.txt if we use glob.glob() option

Barmar Over a year ago

How you get the filename has nothing to do with how you read the file.

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