How to assign dynamic variables in a for loop in python [duplicate]

Question

I have five models for five years as follows.

word2vec_files = ["word2vec_2011", "word2vec_2012", "word2vec_2013", "word2vec_2014", "word2vec_2015"]
years = [2011, 2012, 2013, 2014, 2015]

I want to open each model as model_2011, model_2012, model_2013, model_2014, model_2015.

Currently I am doing it one by one as follows.

model_2011 = word2vec.Word2Vec.load("word2vec_2011")
model_2012 = word2vec.Word2Vec.load("word2vec_2012")
model_2013 = word2vec.Word2Vec.load("word2vec_2013")
model_2014 = word2vec.Word2Vec.load("word2vec_2014")
model_2015 = word2vec.Word2Vec.load("word2vec_2015")

Now I want to imitate the same process using a for loop.

for i, word2vec_file in enumerate(word2vec_files):
    "model_"+str(years[i]) = word2vec.Word2Vec.load(word2vec_file)

However, I get the following error SyntaxError: can't assign to operator. I am wondering how to assign dynamic variables in a for loop in python.

I am happy to provide more details if needed.

OliverRadini · Accepted Answer · 2019-07-30 08:20:35Z

1

Unfortunately you can't create variable from strings like that; but you can use a dictionary, and add keys/values to it:

years = [2011, 2012, 2013, 2014, 2015]

models = {}

for year in years:
  models[year] = word2vec.Word2Vec.load("word2vec_%s" % year)

print(models)

That way, you can access the year on models to get what you need.

You could do the same thing with a dictionary comprehension:

years = [2011, 2012, 2013, 2014, 2015]

models = {
  year: "word2vec_%s" % year
  for year in years
}

print(models)

answered Jul 30, 2019 at 8:20

OliverRadini

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