call base class function in derived class constructor

Question

I know it's OK to call base class function in a derived class constructor, because base class is constructed before derived class.But I'm not sure if this is a good practice.Example code is:

class Base {
 public:
  int Get() const { return i_; }
  void Set(const int i) { i_ = i; }

 private:
  int i_{0};
};

class Derived : public Base {
  // initialize `derived_i_` with a call to base class function, Is this a good
  // practice in production code?
  Derived() : derived_i_{Get()} {
    // do some other things
  }

 private:
  int derived_i_{0};
};

How should Base::Get() ever return something different but 0 when called from the member initialization list of Derived()? — Swordfish
– Swordfish, Commented May 8, 2019 at 2:08

Collin · Accepted Answer · 2019-05-08 03:02:07Z

1

To be more pedantic, you could write your constructor as the following:

Derived() : Base(), derived_i_{Get()} {
  // do some other things
}

The compiler should fully construct the base class before doing any initialization of the derived class.

answered May 8, 2019 at 3:02

Collin

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