Let's say I have this:
$a11 = date("F j, Y, g:i a", $a['date']);
$newTime = date($a['date'], strtotime('+3 hour'));
$b11 = date("F j, Y, g:i a", $newTime);
echo $a11 . " AND " . $b11;
I know $a['date'] is right because I get: March 22, 2011, 10:22 pm. However, the echo produces: March 22, 2011, 10:22 pm AND March 22, 2011, 10:22 pm when clearly the second part is suppose to be three hours ahead.
What am I doing wrong?
Don't you want:
$newTime = strtotime( '+3 hours',$a['date'] );
$b11 = date("F j, Y, g:i a", $newTime );
It seems you provide the wrong order of parameters in $newTime = date($a['date'], strtotime('+3 hour'));. Try this:
<?php
$a['date'] = mktime();
$a11 = date("F j, Y, g:i a", $a['date']);
$newTime = date(strtotime('+3 hour'),$a['date']);
$b11 = date("F j, Y, g:i a", $newTime);
echo $a11 . " AND " . $b11;
?>
Dig it, you are not strtotime'ing the $newTime when converting to date, so it's false.
<?php
$a['date'] = time();
$a11 = date("F j, Y, g:i a", $a['date']);
echo 'Now = ' . time() . PHP_EOL;
echo 'Now +3hrs = ' . strtotime( '+3 hours' ) . PHP_EOL . PHP_EOL;
$newTime = strtotime( '+3 hours' );
$b11 = date("F j, Y, g:i a", $newTime );
echo $a11 . ' and ' . $b11 . PHP_EOL;
The format of date function is: string date ( string $format [, int $timestamp ] ). So, according to the first line, $a['date'] stores the timestamp value. But, according to the second line, its value is date format.
Moreover, you should type "+3 hours".
I add date like following
<?php
$a['date']="March 22, 2011, 10:22 pm";
$a11 = date("F j, Y, g:i a", strtotime($a['date']));
$b11 = strtotime(date("F j, Y, g:i a", strtotime($a['date'])) . " +3 hours");
$b11 = date("F j, Y, g:i a", $b11);
echo $a11 . "AND " . $b11;
?>
