Python: open multiple txt file in a directory [duplicate]

Question

Hi i was going to open multiple txt files in a directory.

But i get error message of

File "testTopic.py", line 9, in <module>
with open(path +i, 'r') as f:
IOError: [Errno 2] No such file or directory:
'C:\Users\Documents\FP\TM\Export28011986676_10155756928931677.txt'

I did import os, and i trying to open files that ends with '.txt' where by my files all are 122343.txt, 344545.txt, 565464353.txt and carry on.

The code you posted does not contain the line the error message is pointing to. The code you posted has entirely different problems. — user2357112
– user2357112, Commented Mar 11, 2018 at 4:32
@user2357112 i have update my post, with a new error message — xxxSL
– xxxSL, Commented Mar 11, 2018 at 4:40

DYZ · Accepted Answer · 2018-03-11 05:02:30Z

1

You need to add a separator between the path and the file name:

path = "C:\Users\Documents\FP\TM\Export\\"

(Mind the slash at the end of the path.)

edited Mar 11, 2018 at 5:02

answered Mar 11, 2018 at 4:50

DYZ

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2 Comments

xxxSL Over a year ago

i tried , but it still cant. File "testTopic.py", line 5 path = "C:\Users\Documents\FP\TM\Export\" ^ SyntaxError: EOL while scanning string literal

DYZ Over a year ago

My bad, I forgot to escape the slash.

python必须死 · Accepted Answer · 2018-03-11 05:00:33Z

0

or:

you can useing os.path.join

import os
os.path.join(path,i)

answered Mar 11, 2018 at 5:00

python必须死

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