Now, I want to set the output generated in constant( first two in letters,last three in numeric). What code should I use? Thanks.
Javascript
function makeid() {
var text = "";
var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
for (var i = 0; i < 5; i++)
text += possible.charAt(Math.floor(Math.random() * possible.length));
return text;
}
console.log(makeid());
You could try separating your 'possible' string into possibleNums and possibleChars
var possibleNums = "0123456789";
var possibleAlpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
for (var i = 0; i < 2; i++) {
text += possibleAlpha.charAt(Math.floor(Math.random() * possibleAlpha.length));
}
for (var i = 0; i < 3; i++) {
text += possibleNums.charAt(Math.floor(Math.random() * possibleNums.length));
}
Try this:
function makeid() {
var text = "";
var possibleLetters = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
var possibleNumbers = "0123456789";
for (var i = 0; i < 2; i++)
text += possibleLetters.charAt(Math.floor(Math.random() * possibleLetters.length));
for (var i = 0; i < 3; i++)
text += possibleNumbers.charAt(Math.floor(Math.random() * possibleNumbers.length));
return text;
}
Here you are -code in ES6-:
You need to separate numbers and characters,
But to generate random unique id you can refer to here
const makeid = () => {
let id = '';
const chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz';
const nums = '0123456789'
for (let i = 0; i < 2; i++) {
id += chars[Math.floor(Math.random() * chars.length) + 1]
}
for (let i = 0; i < 3; i++) {
id += nums[Math.floor(Math.random() * nums.length) + 1]
}
return id
}And here's more functional and readable code:
const makeid = () => {
let id = '';
const chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz';
const nums = '0123456789'
id += generate(2, chars)
id += generate(3, nums)
return id
}
const generate = (number, string) => {
let res = ''
for (let i = 0; i < number; i++) {
res += string[Math.floor(Math.random() * string.length) + 1]
}
return res
}
console.log(makeid())Actually you don't need the string "possible" you can use ascii values.
below is the code.
function makeid() {
var text = "";
var x,y;
for (var i = 0; i < 2; i++){
x=(Math.floor(Math.random()*2))?( Math.floor(Math.random() * (26)) + 65):( Math.floor(Math.random() * (26)) + 97)
text+=String.fromCharCode(x)
}
for (var i = 0; i < 3; i++){
x=String.fromCharCode(Math.floor(Math.random() * (10)) + 48)
text+=x
}
return text;
}
console.log(makeid());
var randomBetween = (min,max)=> Math.floor(max-Math.random()*(max-min));
var randomLetter = ()=> String.fromCharCode(randomBetween(65,90)+(Math.round(Math.random())?32:0));
var makeId = pattern=> (pattern||'xx000').replace(/./g, v=>isNaN(v)?randomLetter():randomBetween(0,9));
console.log(makeId());Or you can also make your own patterns for example:
makeId('aaaaaa11111'); //returns: lUmKUe07356
makeId('a1a1a1a1a1a1a'); //returns: b2N5U8J2m7r2C
Any matching letter will be replaced with a random one, any number with a random number.
You can try the following:
function getRandomId() {
return String.fromCharCode((Math.random() < 0.5 ? 65 : 97) + Math.floor(Math.random() * 26)) +
String.fromCharCode((Math.random() < 0.5 ? 65 : 97) + Math.floor(Math.random() * 26)) +
Math.random().toString(10).substring(2, 5);
}
for (var i = 0; i < 5; i++) {
console.log(getRandomId());
}
/* Sample Output:
wc257
bR495
Li690
cF973
kf790
*/
