Can I construct std::vector with zero elements via the non-default constructor

Question

I mean something like this:

std::vector<T> v(0);

Is it ok? I don't see any requirements like this in the Standard.

There's more than one non-default constructor.

juanchopanza
– juanchopanza

2017-07-11 05:42:56 +00:00
Commented Jul 11, 2017 at 5:42 — juanchopanza
– juanchopanza, Commented Jul 11, 2017 at 5:42

Brian Bi · Accepted Answer · 2017-07-11 04:14:00Z

6

This is well-defined. The standard does not place any restrictions on the value of n passed to this constructor. 0 is a valid value of type size_type (whatever that is).

answered Jul 11, 2017 at 4:14

Brian Bi

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2 Comments

Henri Menke Over a year ago

The standard specifies size_type to be an unsigned integer type. In reality this is unsigned long (at least for stdlibc++).

MSalters Over a year ago

@henri: implementation defined. Msvc in 64 bits mode doesn't, as it would limit the container size to 4 billion.

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