How to use a variable in a curl URL in shell script?

Question

I am trying to use curl with a URL containing two dates. How can I use the values of two variables containing date/time stamps instead of hard coded dates in the URL? I want to use a range from 50 minutes ago to the current time.

Here is my code with hard coded date/time values:

#!/bin/bash

currentTime=$(date +"%R")
currentdate=$(date +'%m/%d/%Y')
oldtime=$(date +%R -d "50 min ago")

echo "Current time : $currentTime"
echo "Current Date : $currentdate"
echo "Old time : $oldtime"

Response=$(curl -X GET -H "Authorization: Basic Token=" "http://targetserver.companyname.com:8080/v1/organizations/companyname/environments/environmentname/stats/apis?select=sum(is_error)&timeRange=01/24/2017%2002:00~01/25/2017%2006:00")

I tried replacing the hard coded dates as follows, but it didn't work:

Response=$(curl -X GET -H "Authorization: Basic Token=" "http://targetserver.company.com:8080/v1/organizations/company/environments/environmentname/stats/apis?select=sum(is_error)&timeRange="$currentdate" "$currentTime"~"$currentdate" "$oldtime"")

Could you show at least one way you tried? Also, what does this have to do with r? — chepner
– chepner, Commented Jan 26, 2017 at 14:18
You know how to use a variable in a string - you have used in echo statements. You can use the same mechanism in the curl statement. — anishsane
– anishsane, Commented Jan 26, 2017 at 14:41
Hi chepner ... please see below the way I was trying ... Response=$(curl -X GET -H "Authorization: Basic Token=" "targetserver.companyname.com:8080/v1/organizations/companyname/…) echo -e "The response is :\n $Response" value=$(Response|jsawk 'return this.values') echo "the value is : $value" The error is "command not found" I am using cygwin, and tried downloading different js package but still not working. — A. Datta
– A. Datta, Commented Jan 26, 2017 at 15:24
Response=$(curl -X GET -H "Authorization: Basic Token=" "targetserver.company.com:8080/v1/organizations/company/…) echo -e "the response is: \n $Response" Tried but did not work. — A. Datta
– A. Datta, Commented Jan 26, 2017 at 19:55
Hi Chepner please see the below command. It's not working though. Response=$(curl -X GET -H "Authorization: Basic Token=" "targetserver.company.com:8080/v1/organizations/company/…) echo -e "the response is: \n $Response" — A. Datta
– A. Datta, Commented Jan 26, 2017 at 20:47

Ashley Primo · Accepted Answer · 2017-01-26 23:23:45Z

2

Response=$(curl -X GET -H "Authorization: Basic Token=" "http://targetserver.company.com:8080/v1/organizations/company/environments/environmentname/stats/apis?select=sum(is_error)&timeRange=${currentdate}%20${currentTime}~${currentdate}%20${oldtime}")

I made a working example, here:

#!/bin/bash
example="Just_A_Test_String"
response=$(curl -X GET "http://5.135.224.191/test_curl.php?var1=${example}")
echo $response

answered Jan 26, 2017 at 23:23

Ashley Primo

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2 Comments

Charles Duffy Over a year ago

echo "$response" would be a bit less buggy with the double quotes; see BashPitfalls #14.

Ashley Primo Over a year ago

Completely agree @CharlesDuffy - I normally do that, however slipped my mind at the time.

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