Java getting the Enum name given the Enum Value

Question

How can I get the name of a Java Enum type given its value?

I have the following code which works for a particular Enum type, can I make it more generic?

public enum Category {

    APPLE("3"), 
    ORANGE("1"), 

    private final String identifier;

    private Category(String identifier) {
        this.identifier = identifier;
    }

    public String toString() {
        return identifier;
    }

    public static String getEnumNameForValue(Object value){
        Category[] values = Category.values();
        String enumValue = null;
        for(Category eachValue : values) {
            enumValue = eachValue.toString();

            if (enumValue.equalsIgnoreCase(value)) {
                return eachValue.name();
            }
        }
        return enumValue;
    }
}

Is there a special reason why you want to use something other than the name() of the Enum for looking them up? That would confuse a lot of people, and you also cannot use a simple Category.valueOf(name). — Thilo
– Thilo, Commented Oct 8, 2010 at 9:36
Really can we make it more generic? I am using a lot of nameOf(String name), now for each I will write a *Enum.values().stream().filter(...).findAny().get(), which is so annoying. — Hearen
– Hearen, Commented May 18, 2018 at 12:33

thSoft · Accepted Answer · 2013-10-15 15:47:23Z

60

You should replace your getEnumNameForValue by a call to the name() method.

edited Oct 15, 2013 at 15:47

thSoft

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answered Oct 8, 2010 at 9:26

Riduidel

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5 Comments

trashgod Over a year ago

@Jukia: Also, consider overriding toString(): download.oracle.com/javase/6/docs/api/java/lang/…

Thilo Over a year ago

@trashgod: She is overriding toString

trashgod Over a year ago

@Thilo: My error; thanks. @Julia: Sorry about misspelling your name.

kayesh parvez Over a year ago

@trashgod: Julia wanted to pass the value. How to pass the value as parameter in name() function ?

trashgod Over a year ago

@kayeshparvez: I've used a Map of values(), as discussed here.

Victor Ionescu · Accepted Answer · 2020-01-10 14:55:57Z

49

Try below code

public enum SalaryHeadMasterEnum {

    BASIC_PAY("basic pay"),
    MEDICAL_ALLOWANCE("Medical Allowance");

    private String name;

    private SalaryHeadMasterEnum(String stringVal) {
        name=stringVal;
    }
    public String toString(){
        return name;
    }

    public static String getEnumByString(String code){
        for(SalaryHeadMasterEnum e : SalaryHeadMasterEnum.values()){
            if(e.name.equals(code)) return e.name();
        }
        return null;
    }
}

Now you can use below code to retrieve the Enum by Value

SalaryHeadMasterEnum.getEnumByString("Basic Pay")

Use Below code to get ENUM as String

SalaryHeadMasterEnum.BASIC_PAY.name()

Use below code to get string Value for enum

SalaryHeadMasterEnum.BASIC_PAY.toString()

edited Jan 10, 2020 at 14:55

Victor Ionescu

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answered Jun 15, 2013 at 9:43

prashant thakre

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3 Comments

f_puras Over a year ago

code == e.name is not going to work the way you meant it to, should be e.name.equals(code) instead

f_puras Over a year ago

Well, yes: SalaryHeadMasterEnum.getEnumByString("basic pay") does work, but relies on the JVM merging String literals. Stuff like SalaryHeadMasterEnum.getEnumByString(new StringBuilder("basic ").append("pay").toString()) does not, but should IMHO. Using String.equals() would make both work ;-)

Hardcoded Over a year ago

- for comparing strings with == which is bad and for using a variable 'name' with a different meaning than the 'name()' method

Javaci · Accepted Answer · 2016-10-20 11:07:10Z

5

Try, the following code..

    @Override
    public String toString() {
    return this.name();
    }

answered Oct 20, 2016 at 11:07

Javaci

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1 Comment

Mayuso Over a year ago

This should work well, but why call the function toString() instead of getName() (Or something similar) ?

Fejs · Accepted Answer · 2017-09-08 08:28:37Z

Here is the below code, it will return the Enum name from Enum value.

public enum Test {

    PLUS("Plus One"), MINUS("MinusTwo"), TIMES("MultiplyByFour"), DIVIDE(
            "DivideByZero");
    private String operationName;

    private Test(final String operationName) {
        setOperationName(operationName);
    }

    public String getOperationName() {
        return operationName;
    }

    public void setOperationName(final String operationName) {
        this.operationName = operationName;
    }

    public static Test getOperationName(final String operationName) {

        for (Test oprname : Test.values()) {
            if (operationName.equals(oprname.toString())) {
                return oprname;
            }
        }
        return null;
    }

    @Override
    public String toString() {
        return operationName;
    }
}

public class Main {
    public static void main(String[] args) {

        Test test = Test.getOperationName("Plus One");
        switch (test) {
        case PLUS:
            System.out.println("Plus.....");
            break;
        case MINUS:
            System.out.println("Minus.....");
            break;

        default:
            System.out.println("Nothing..");
            break;
        }
    }
}

alps_ren · Accepted Answer · 2019-11-14 20:49:36Z

1

In such cases, you can convert the values of enum to a List and stream through it. Something like below examples. I would recommend using filter().

Using ForEach:

List<Category> category = Arrays.asList(Category.values());
category.stream().forEach(eachCategory -> {
            if(eachCategory.toString().equals("3")){
                String name = eachCategory.name();
            }
        });

Or, using Filter:

When you want to find with code:

List<Category> categoryList = Arrays.asList(Category.values());
Category category = categoryList.stream().filter(eachCategory -> eachCategory.toString().equals("3")).findAny().orElse(null);

System.out.println(category.toString() + " " + category.name());

When you want to find with name:

List<Category> categoryList = Arrays.asList(Category.values());
Category category = categoryList.stream().filter(eachCategory -> eachCategory.name().equals("Apple")).findAny().orElse(null);

System.out.println(category.toString() + " " + category.name());

Hope it helps! I know this is a very old post, but someone can get help.

edited Nov 14, 2019 at 20:49

answered Nov 14, 2019 at 20:44

alps_ren

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1 Comment

Piyush Upadhyay Over a year ago

A "NullPointerException" could be thrown; "orElse()" can return null in case of "When you want to find with name:" flow.

nilesh parmar · Accepted Answer · 2022-09-24 14:25:40Z

1

enum MyEnum {
    ENUM_A("A"),
    ENUM_B("B");

    private String name;
   
    private static final Map<String,MyEnum> unmodifiableMap;

    MyEnum (String name) {
        this.name = name;
    }

    public String getName() {
        return this.name;
    }

    static {
        Map<String,MyEnum> map = new ConcurrentHashMap<String, MyEnum>();
        for (MyEnum instance : MyEnum.values()) {
            map.put(instance.getName().toLowerCase(),instance);
        }
        unmodifiableMap = Collections.unmodifiableMap(map);
    }
    public static MyEnum get (String name) {
        return unmodifiableMap.get(name.toLowerCase());
    }
}

Now you can use below code to retrieve the Enum by Value

MyEnum.get("A");

edited Sep 24, 2022 at 14:25

answered Sep 24, 2022 at 14:23

nilesh parmar

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Comments

karel · Accepted Answer · 2022-05-02 02:17:18Z

0

I believe it's better to provide the required method in the enum itself. This is how I fetch Enum Name for a given value. This works for CONSTANT("value") type of enums.

public enum WalletType {
    UPI("upi-paymode"),
    PAYTM("paytm-paymode"),
    GPAY("google-pay");

    private String walletType;
        WalletType(String walletType) {
            this.walletType = walletType;
        }
    
    public String getWalletType() {
        return walletTypeValue;
    }
    
    public WalletType getByValue(String value) {
        return Arrays.stream(WalletType.values()).filter(wallet -> wallet.getWalletType().equalsIgnoreCase(value)).findFirst().get();
    }
}

e.g. WalletType.getByValue("google-pay").name() this will give you - GPAY

edited May 2, 2022 at 2:17

karel

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answered May 1, 2022 at 10:23

Aadil Minhaz

1

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