Java - Method Overloading

Question

I am having a trouble with Method Overloading I was ask to create a program that will enter an operator and 2 operands. Overload the method named getAnswer as follows: -

get its sum by calling the method
get its difference by calling the method and pass the operands on that method.
get its product by calling the method and returns a value.
get its quotient by calling a method and returns a value and pass the operands on that method.

Here's my code:

import java.util.Scanner;

public class MethodHomework2
{
    int a, b;
    public void getAnswer()
    {
        int sum = a + b;
        System.out.println("The sum is: " + sum);
    }
    public void getAnswer(int a, int b)
    {
        int diff = a - b;
        System.out.println("The difference is: " + diff);
    }
    public int getAnswer()
    {
        int prod = a * b;
        return prod;
    }
    public int getAnswer(int a, int b)
    {
        int quot = a / b;
        return quot;
    }
    public static void main (String args[])
    {   
       MethodHomework2 mh = new MethodHomework2();
       Scanner kb = new Scanner(System.in);
       int returnValue;

       System.out.print("Enter 2 number: ");
       a = kb.nextInt();
       b = kb.nextInt();

        mh.getAnswer();
        mh.getAnswer(c, d);
        returnValue = mh.getAnswer();
        System.out.println("The product is: " + returnValue);
        returnValue = mh.getAnswer(c, d);
        System.out.println("The quotient is: " + returnValue);
    }
}

You don't necessarily need to overload your methods for this. — Freddy
– Freddy, Commented Jul 6, 2016 at 2:21
when calling getAnswer () - how would it know which one to use? — Scary Wombat
– Scary Wombat, Commented Jul 6, 2016 at 2:36
getAnswer() for diff and getAnswer() for quot is not the way overloading is done as they both have same signature — bananas
– bananas, Commented Jul 6, 2016 at 4:14
Passing the different types of argument lists only make the signature of method be unique. So try different datatypes to achieve method overloading. Otherwise, the manipulation you are doing in your program seems like operator overloading. The simple way to remember this Overloading is compiler time polymorphism and the compiler would never allow duplication of variables where methods with same arguments and different return types or different access modifier are considered as duplicate methods. — S.K. Venkat
– S.K. Venkat, Commented Jul 6, 2016 at 4:17

Wilson · Accepted Answer · 2016-07-06 04:19:07Z

1

You can have a look to Overloading Methods:

Java can distinguish between methods with different method signatures. This means that methods within a class can have the same name if they have different parameter lists.

Overloaded methods are differentiated by the number and the type of the arguments passed into the method.

In your code example, int getAnswer() and int getAnswer(int a, int b) are distinct and unique methods because they require different parameter lists.

The compiler does not consider return type when differentiating methods, so you cannot declare two methods with the same signature even if they have a different return type.

There will be compilcation error when you declare method of void getAnswer() and int getAnswer() since the 2 methods are declared with same signature:

java: method getAnswer() is already defined in class MethodHomework2

edited Jul 6, 2016 at 4:19

answered Jul 6, 2016 at 2:57

Wilson

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Comments

Ishan Lakshitha · Accepted Answer · 2018-10-13 05:43:00Z

0

Method Overloading

Same name different parameters

myMethod(int x)
myMethod(int x, int y)

answered Oct 13, 2018 at 5:43

Ishan Lakshitha

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Supun Sandaruwan · Accepted Answer · 2021-06-03 17:45:48Z

0

In java, there is three different ways to method overloading.

By changing the number of parameters in two methods.
```
void add(){}

void add(int a){}
```
By changing data types of the parameters of methods.
```
void add(int a){}

void add(float a){}
```

By changing Order of the parameters of methods.

void add(int a, String b){}

void add(String a, int b){}

answered Jun 3, 2021 at 17:45

Supun Sandaruwan

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