Error "(unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape" [duplicate]

This error occurs, because you are using a normal string as a path. You can use one of the three following solutions to fix your problem:

1: Just put r before your normal string. It converts a normal string to a raw string:

pandas.read_csv(r"C:\Users\DeePak\Desktop\myac.csv")

2:

pandas.read_csv("C:/Users/DeePak/Desktop/myac.csv")

3:

pandas.read_csv("C:\\Users\\DeePak\\Desktop\\myac.csv")

The first backslash in your string is being interpreted as a special character. In fact, because it's followed by a "U", it's being interpreted as the start of a Unicode code point.

To fix this, you need to escape the backslashes in the string. The direct way to do this is by doubling the backslashes:

data = open("C:\\Users\\miche\\Documents\\school\\jaar2\\MIK\\2.6\\vektis_agb_zorgverlener")

If you don't want to escape backslashes in a string, and you don't have any need for escape codes or quotation marks in the string, you can instead use a "raw" string, using "r" just before it, like so:

data = open(r"C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener")

You can just put r in front of the string with your actual path, which denotes a raw string. For example:

data = open(r"C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener")

Consider it as a raw string. Just as a simple answer, add r before your Windows path.

 import csv

 data = open(r"C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener")
 data = csv.reader(data)
 print(data)

Try writing the file path as "C:\\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener" i.e with double backslash after the drive as opposed to "C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener"

Add r before your string. It converts a normal string to a raw string.

As per String literals:

String literals can be enclosed within single quotes (i.e. '...') or double quotes (i.e. "..."). They can also be enclosed in matching groups of three single or double quotes (these are generally referred to as triple-quoted strings).

The backslash character (i.e. \) is used to escape characters which otherwise will have a special meaning, such as newline, backslash itself, or the quote character. String literals may optionally be prefixed with a letter r or R. Such strings are called raw strings and use different rules for backslash escape sequences.

In triple-quoted strings, unescaped newlines and quotes are allowed, except that the three unescaped quotes in a row terminate the string.

Unless an r or R prefix is present, escape sequences in strings are interpreted according to rules similar to those used by Standard C.

So ideally you need to replace the line:

data = open("C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener")

To any one of the following characters:

• Using raw prefix and single quotes (i.e. '...'):

    data = open(r'C:\Users\miche\Documents\school\jaar2\MIK\2.6\vektis_agb_zorgverlener')
  

• Using double quotes (i.e. "...") and escaping backslash character (i.e. \):

    data = open("C:\\Users\\miche\\Documents\\school\\jaar2\\MIK\\2.6\\vektis_agb_zorgverlener")
  

• Using double quotes (i.e. "...") and forwardslash character (i.e. /):

    data = open("C:/Users/miche/Documents/school/jaar2/MIK/2.6/vektis_agb_zorgverlener")
  

Just putting an r in front works well.

eg:

  white = pd.read_csv(r"C:\Users\hydro\a.csv")

It worked for me by neutralizing the '' by f = open('F:\\file.csv')

The double \ should work for Windows, but you still need to take care of the folders you mention in your path. All of them (except the filename) must exist. Otherwise you will get an error.