Laravel 5 Form request validation with parameters

Question

I am using form request validation and there are some rules that needs external values as a parameters.

Here are my validation rules for editing a business profile inside a form request class,

public function rules()
{
    return [
        'name' => 'required|unique:businesses,name,'.$business->id,
        'url' => 'required|url|unique:businesses'
    ];
}

I can use this on the controller by type hinting it.

public function postBusinessEdit(BusinessEditRequest $request, Business $business)
{
    //
}

But how to pass the $business object as a parameter to the rules method?

import the model(i assume $business is a model) into your request class & get the object manually — Nehal Hasnayeen
– Nehal Hasnayeen, Commented Jul 16, 2015 at 1:44
@NehalHasnayeen yes the business is a model but it is type hinted on to the controller method that uses route model bindings. — Dipendra Gurung
– Dipendra Gurung, Commented Jul 16, 2015 at 1:58

Sh1d0w · Accepted Answer · 2015-07-18 15:52:55Z

10

Lets say this is your model binding:

$router->model('business', 'App\Business');

Then you can reference the Business class from within the FormRequest object like this:

public function rules()
{
    $business = $this->route()->getParameter('business');
    // rest of the code
}

Note that if you use your form request both for create and update validation, while creating the record, the business variable will be null because your object does not exists yet. So take care to make the needed checks before referencing the object properties or methods.

edited Jul 18, 2015 at 15:52

answered Jul 16, 2015 at 2:30

Sh1d0w

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1 Comment

ml59 Over a year ago

you can do shorter $this->route('business')

pinkal vansia · Accepted Answer · 2015-07-16 06:10:46Z

9

There can be many ways to achieve this. I do it as below.

You can have a hidden field 'id' in your business form like bellow,

{!! Form::hidden('id', $business->id) !!}

and you can retrieve this id in FormRequest as below,

public function rules()
{
    $businessId = $this->input('id');

    return [
        'name' => 'required|unique:businesses,name,'.$businessId,
        'url' => 'required|url|unique:businesses'
    ];
}

answered Jul 16, 2015 at 6:10

pinkal vansia

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1 Comment

Anderson Madeira Over a year ago

I think this answer is simpler than the accepted answer.

FabienChn · Accepted Answer · 2017-07-24 15:00:15Z

5

For those who switched to laravel 5 :

public function rules()
{
    $business = $this->route('business');
    // rest of the code
}

answered Jul 24, 2017 at 15:00

FabienChn

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Comments

DavidODW · Accepted Answer · 2017-11-17 06:10:58Z

1

Let say if we have a scenario like we want to change our validation rules depends on the type that we pass in with the route. For example:

app.dev/business/{type}

For different type of business, we have different validation rules. All we need to do is type-hint the request on your controller method.

public function store(StoreBusiness $request)
{
    // The incoming request is valid...
}

For the custom form request

class StoreBussiness extends FormRequest
{

    public function rules()
    {
        $type = $this->route()->parameter('type');

        $rules = [];
        if ($type === 'a') {
        }

        return rules;
    }
}

answered Nov 17, 2017 at 6:10

DavidODW

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Comments

godbout · Accepted Answer · 2018-01-22 09:54:06Z

1

In Laravel 5.5 at least (haven't checked older versions), once you did your explicit binding (https://laravel.com/docs/5.5/routing#route-model-binding), you can get your model directly through $this:

class StoreBussiness extends FormRequest
{

    public function rules()
    {
        $rules = [];
        if ($this->type === 'a') {
        }

        return rules;
    }
}

answered Jan 22, 2018 at 9:54

godbout

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Comments

Adam · Accepted Answer · 2020-02-15 22:04:10Z

1

Since Laravel 5.6 you may type hint it in the rules method:

public function rules(Business $business)
{
    return [
        'name' => 'required|unique:businesses,name,'.$business->id,
        'url' => 'required|url|unique:businesses'
    ];
}

See the docs for more:

You may type-hint any dependencies you need within the rules method's signature. They will automatically be resolved via the Laravel service container.

answered Feb 15, 2020 at 22:04

Adam

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4 Comments

zacktagnan Over a year ago

Adam ... for example, if you have public function update(BusinessUpdateRequest $request, Business $business) {...} on the BusinessController.php, how do you pass the $business to the BusinessUpdateRequest.php so you can uses this parameter on the "rules" method like you do on your example???

Adam Over a year ago

@zacktagnan you need to bind $business to the server container. It will be resolved automatically :)

zacktagnan Over a year ago

Adam ... Sorry, but I don't know how to "bind $business to the server container" Could you do an example of that?

Adam Over a year ago

@zacktagnan create a service provider and bind your class. Read laravel.com/docs/7.x/container and laravel.com/docs/7.x/providers#the-register-method to get started

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