C++ Inheritance of functions with same name

Question

I have the following class declarations:

class human
{
    public:
    void msg(){cout<<"I am human\n";}
};
class John:public human 
{
    public:
    void msg(){cout<<"I am a John\n";}
};

As it is clear the class John and human both have a function msg(). Clearly , the class John is inheriting resources from human. Now when I create an object of the derived class and call msg():

John a;
a.msg();

The output is :

I am John

But doesnt John inherit msg() from human?

Also is there a way to access msg() of human by using an object of the derived class?

EDIT:

Yup calling the function like so will help me

a.human::msg()

Another question :

Also if I modify the class like so:

class human
{
    protected:
    void msg(){cout<<"I am human\n";}
};
class John:public human 
{
    public:
    void msg(){cout<<"I am a John\n";}
};

Now how can I access the msg() of human.

πάντα ῥεῖ · Accepted Answer · 2015-03-20 17:43:20Z

5

"But doesnt John inherit msg() from human?"

Yes it does, but hides it with its own implementation.

"Also is there a way to access msg() of human?"

Yes, you need to explicitly state the class scope (as long human::msg() is in public scope as it was originally asked):

  John a;
  a.human::msg();
 // ^^^^^^^

The same syntax needs to be applied if you want to access human::msg() from within class John:

class John : public human {
    public:
    void msg() {cout<<"I am a John\n";}
    void org_msg() { human::msg(); }
};

John a;
a.org_msg();

or another alternative

John john;
human* h = &john;
h->msg();

edited Mar 20, 2015 at 17:43

answered Mar 20, 2015 at 17:22

πάντα ῥεῖ

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