Try-Catch block getting length of string error

Question

I have everything working but I am having an issue with the JTextField. When the user submits nothing, it should be returning null rather than 0. So far it's returning 0, but I need it to return NULL. It's not reaching the Catch block at all even if I put System.out.println("test"); it's not reaching there.

import javax.swing.*;
import javax.*;
import javax.swing.JFrame;

import java.awt.*;
import java.awt.event.*;


public class stringlength implements ActionListener {

  public static JLabel outputLabel;
  public static JTextField inputField = new JTextField(20);

  public static void main(String[] args) {

    stringlength myWindow = new stringlength ();

  }

  public stringlength (){
    JFrame frame = new JFrame("stringlength");
    frame.setVisible(true);
    frame.setSize(500,100);
    //frame.setLayout(new GridLayout(1,3));
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

    JPanel panel = new JPanel();
    frame.add(panel);

    outputLabel = new JLabel("String length = ");
    JButton stringLengthButton = new JButton("Get String Length");
    stringLengthButton.addActionListener(this);


    panel.add(stringLengthButton);
    panel.add(outputLabel);
    panel.add(inputField);

  }


  public void actionPerformed(ActionEvent e) {

    try{
    String text = inputField.getText();
    System.out.println(text);
    outputLabel.setText("String length = " + text.length());
    }
    catch(NullPointerException e1)
    {
        e1.printStackTrace();

    }
  }

}

No really, why are you catching a NullPointerException?

Makoto
– Makoto

2015-03-12 15:19:18 +00:00
Commented Mar 12, 2015 at 15:19 — Makoto
– Makoto, Commented Mar 12, 2015 at 15:19

Brian A. Henning · Accepted Answer · 2015-03-12 15:19:12Z

1

getText() will never return null. If you want a null value, or an exception, you will have to detect a zero-length string and return null or throw the exception yourself.

JavaDoc for getText()

answered Mar 12, 2015 at 15:19

Brian A. Henning

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Comments

davide · Accepted Answer · 2015-03-12 15:18:01Z

0

public void actionPerformed(ActionEvent e) {

  try{
    String text = inputField.getText();
    System.out.println(text);
    outputLabel.setText("String length = " + text.length());
    if (text.length()==0)
      throw new NullPointerException();
    }
    catch(NullPointerException e1)
    {
      e1.printStackTrace();
    }
 }

edited Mar 12, 2015 at 15:18

davide

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answered Mar 12, 2015 at 15:16

René Winkler

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Comments

Damo42 · Accepted Answer · 2015-03-13 22:19:44Z

Let me ask you... What if you can return null. Is your code supposed to give the user a second try at entering a string ?? if so then try

    try
        {
        firstTry = inputField.getText();
            if(firstTry.length() == 0)
                {
                    outputLabel.setText("String Length = "+secondTry.length());
                }
            else
                {
                outputLabel.setText("String length = "+firstTry.length());
                }
        }//end try
    catch(NullPointerException e1)
        {
            secondTry=JOptionPane.showInputDialog ( "empty try again" );
            outputLabel.setText("String Length = "+secondTry.length());
        }//end catch

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