Saving images from dynamic PHP url

Question

I'm trying to save a jpg file from a dynamic url, looks like this,

http://bks7.books.google.se/books?id=TL3JGsUOArkC&printsec=frontcover&img=1&zoom=1&&source=gbs_api

file_get_contents can't get the content correctly, here is my code,

<?php
$image_url = "http://bks7.books.google.se/books?id=TL3JGsUOArkC&printsec=frontcover&img=1&zoom=1&&source=gbs_api";
$img =  file_get_contents($image_url);
$folder = 'C:/xampp/htdocs/test/test.jpg';
file_put_contents($folder, file_get_contents($img));
?>

Appreciate any ideas or alternative as "easy" methods.

oliakaoil · Accepted Answer · 2014-11-14 21:59:12Z

2

One problem is that you have 2 file_get_contents calls. The first call:

$img =  file_get_contents($image_url);

Returns the response from the request to the URL and stores it in the $img variable. The second call:

file_put_contents($folder, file_get_contents($img));

Doesn't make any sense. Instead, just do this:

file_put_contents($folder, $img );

answered Nov 14, 2014 at 21:59

oliakaoil

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1 Comment

D_Guy13 Over a year ago

Wow, How stupid of me :) Thank you, I wasted 45 minutes on that.

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