convert string array to int

Question

I am trying to convert a array with text and numbers to an int.

the array separated:

separated[0] some text
separated[1] 1
separated[2] some more text

What I want is that the [1] ends up being a int.

I tried:

int logSetting = Integer.parseInt(String.valueOf(separated));

and

int logSetting = Integer.parseInt(String.valueOf(separated[1]));

Both made the app crash

09-16 09:57:30.865: E/AndroidRuntime(27938): FATAL EXCEPTION: main

09-16 09:57:30.865: E/AndroidRuntime(27938): Process: my.project, PID: 27938
09-16 09:57:30.865: E/AndroidRuntime(27938): java.lang.NumberFormatException: Invalid int:

"[Ljava.lang.String;@42b273f0"

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.invalidInt(Integer.java:137)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parse(Integer.java:374)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parseInt(Integer.java:365)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.Integer.parseInt(Integer.java:331)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity.fileReader(MainActivity.java:928)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity.logCat(MainActivity.java:944)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at my.project.MainActivity$1.run(MainActivity.java:854)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Handler.handleCallback(Handler.java:733)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Handler.dispatchMessage(Handler.java:95)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.os.Looper.loop(Looper.java:157)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at android.app.ActivityThread.main(ActivityThread.java:5356)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.reflect.Method.invokeNative(Native Method)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at java.lang.reflect.Method.invoke(Method.java:515)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1265)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1081)

09-16 09:57:30.865: E/AndroidRuntime(27938):  at dalvik.system.NativeStart.main(Native Method)

What kind of "crash" happened in second case? Please post the stack trace. — AlexR
– AlexR, Commented Sep 16, 2014 at 7:54
did you try Integer.parseInt(separated[1]);? if you do Integer.parseInt(separated[0]); it should throw error, because text can't convert to int — lakshman
– lakshman, Commented Sep 16, 2014 at 7:55

Ruchira Gayan Ranaweera · Accepted Answer · 2014-09-16 07:55:25Z

4

You can do something like this

String[] separated=new String[]{"some text ","1","some more text"};
int logSetting = 0;
  for(String i:separated){
     try {
        logSetting = Integer.parseInt(i);
      }catch (NumberFormatException e){
        System.out.println("NumberFormatException \""+i+"\" is not a number");
      }
     }
  System.out.println(logSetting);

Out put:

 NumberFormatException "some text " is not a number
 NumberFormatException "some more text" is not a number
 1

answered Sep 16, 2014 at 7:55

Ruchira Gayan Ranaweera

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Comments

Le Ish Man · Accepted Answer · 2014-09-16 07:56:26Z

1

You're almost there, int logSetting = Integer.parseInt(String.valueOf(separated[1])); should just be int logSetting = Integer.parseInt(separated[1]);. If this doesn't work its probably something else crashing your code. What error do you get?

answered Sep 16, 2014 at 7:56

Le Ish Man

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2 Comments

Kick Buttowski Over a year ago

are you sure about your answer? the op got numberformatexcepion

Le Ish Man Over a year ago

If all he has in the index [1] is "1" this should not throw the exception. If it does I have no idea what is wrong.

Kick Buttowski · Accepted Answer · 2014-09-16 08:05:24Z

0

Based on your exception which is NumberFormatException, when you try to convert a String to a numeric value, like an int, float, double, long, etc which does not have right format

For example:

public class ConvertStringToNumber
{

  public static void main(String[] args)
  {
    try
    {
      String s = "FOOBAR";
      int i = Integer.parseInt(s); <--this line of code will never be reached
      System.out.println("int value = " + i);
    }
    catch (NumberFormatException nfe)
    {
      nfe.printStackTrace();
    }
  }

answered Sep 16, 2014 at 8:05

Kick Buttowski

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