php call anonymous functions inside anonymous function [duplicate]

Question

Php version : 5.4

function foo(callable $succCallback) {

        $isCallable = is_callable($succCallback);
        echo "is callable outer ".is_callable($succCallback);
        $success = function($fileInfo) {
            echo "<br>is callable inner".is_callable($succCallback);
        };
        $this->calllll($success);
}
function calllll(callable $foo) {
  $foo("hello");
}

I define a function like that

And the output is

is callable outer 1
is callable inner

How can I refer to the $succCallback inside $success's body.

hindmost · Accepted Answer · 2014-07-21 08:26:37Z

6

You have to use use construct. It allows to inherit variables from the parent scope:

function foo(callable $succCallback) {

        $isCallable = is_callable($succCallback);
        echo "is callable outer ".is_callable($succCallback);
        $success = function($fileInfo) use($succCallback) {
            echo "<br>is callable inner".is_callable($succCallback);
        };
        $this->calllll($success);
}

answered Jul 21, 2014 at 8:26

hindmost

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deceze · Accepted Answer · 2014-07-21 08:26:46Z

2

$success = function ($fileInfo) use ($succCallback) {
    echo "<br>is callable inner" . is_callable($succCallback);
};

To include variables from the surrounding scope inside anonymous functions, you need to explicitly extend their scope using use ().

answered Jul 21, 2014 at 8:26

deceze♦

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Comments

Niet the Dark Absol · Accepted Answer · 2014-07-21 08:27:11Z

2

To use variables from the parent scope, use use:

 $success = function($fileInfo) use ($succCallback) {
        echo "<br>is callable inner".is_callable($succCallback);
    };

answered Jul 21, 2014 at 8:27

Niet the Dark Absol

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