Why I still get object object error in javascript?

Question

I have this javascript to update a php session variable :

  $(document).ready(function(){
        $('#facebook_img').live('click',function(){
login_condetion = 1;                
$.ajax({
                type: "POST",
                url: 'facebook_login_condition_variable.php',
                data:{login_condetion:login_condetion},
                dataType: "json",
                success: function(data)
                {
                    alert(123);
                },
                error : function(XMLHttpRequest, textStatus, errorThrown) {
                    /*alert(XMLHttpRequest);
                    alert(textStatus);
                    alert(errorThrown);
                    alert(XMLHttpRequest.responseText);*/
                }
            });
        });
    });

I print the session value before and after this code but it never change and when I alert responsText I get nothing and XMLHttpRequest gives me object object error .

This is my php code :

<?php 
$temp = $_POST['login_condetion'];
if(!empty($temp) && $temp != 0)
{
   $_SESSION['do_not_allow_auto_facebook_login'] = 1;
}
else    
{
    $_SESSION['do_not_allow_auto_facebook_login'] = 0;
}
$go = $_SESSION;
echo json_encode($go);
?>

Is there any problem with dataType of ajax function ? or it is a php session problem ? Please help me because I have been stuck here for long time.

Not sure if this matters, but "condition" is correctly spelled in some code and in other code, misspelled "condetion" — Paul
– Paul, Commented Jun 3, 2014 at 11:28
Are you calling session_start() in the top of your PHP file? — user1299518
– user1299518, Commented Jun 3, 2014 at 11:30

Deepu Sasidharan · Accepted Answer · 2014-06-03 11:37:25Z

2

Some suggestions..

Do you start the session at top of the page where you use it.

session_start();
in php code replace

$go = $_SESSION;

with

 $go = $_SESSION['do_not_allow_auto_facebook_login'];

3.Do you need the datatype json, if not remove this line

echo json_encode($go);

and use

echo $go;

answered Jun 3, 2014 at 11:37

Deepu Sasidharan

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Comments

jgroenen · Accepted Answer · 2014-06-03 11:32:43Z

2

Use session_start() at the top of your script:

<?php
session_start();
...

answered Jun 3, 2014 at 11:32

jgroenen

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