why i get object object error?

Question

I have a simple ajax request to change the value of some php session variable I still get object object error no matter how I changed the code :

JS code:

$(document).ready(function(){
    $('#facebook_img').live('click',function(){
        login_condetion=1;
        $.ajax({
            type: "POST",
            url: 'facebook_login_condition_variable.php',
            data:{login_condetion:login_condetion},
            success: function()
            {
                alert('test');
            },
            error : function(XMLHttpRequest, textStatus, errorThrown) {
                alert(XMLHttpRequest);  
                alert(textStatus);
                alert(errorThrown);
                alert(XMLHttpRequest.responseText);
            }
        });

    });
});

facebook_login_condition_variable.php :

   <?php 
    $temp = $_POST['login_condetion'];
    if(!empty($temp) && $temp != 0)
    {
       $_SESSION['do_not_allow_auto_facebook_login'] = 1;
    }
    else    
    {
        $_SESSION['do_not_allow_auto_facebook_login'] = 0;  
    }
    ?>

I tried a lot of ajax form but same error and I get nothing when I alert responseText I do not understand why I still get that error ? I hope to find some help here thank u

login_condetion != login_condition

scragar
– scragar

2014-06-02 14:27:51 +00:00
Commented Jun 2, 2014 at 14:27 — scragar
– scragar, Commented Jun 2, 2014 at 14:27
I fix this syntax error but nothing changed same error :(

Basel
– Basel

2014-06-02 14:34:35 +00:00
Commented Jun 2, 2014 at 14:34 — Basel
– Basel, Commented Jun 2, 2014 at 14:34

BastienSander · Accepted Answer · 2014-06-02 14:28:38Z

2

This is not an error... It means that the variables you try to alert are objects.

If you want to see the content of it, replace alert by console.log and see the javascript console of your browser...

answered Jun 2, 2014 at 14:28

BastienSander

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3 Comments

john Smith Over a year ago

i would recommend "console.dir()" for looking at objects

Basel Over a year ago

What I should pass to the console.log or console.dir my success function do not get any value or array or obj back ?

BastienSander Over a year ago

Because you will see the error message in your console... It's not you success function you need to log but XMLHttpRequest, textStatus and errorThrown as : console.dir(XMLHttpRequest); console.dir(textStatus); console.dir(errorThrown);

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