Exception in thread "main java.util.InputMismatchException

Question

I keep getting an error message from the output

Exception in thread "main java.util.InputMismatchException        

    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextDouble(Unknown Source)
    at test1.TC1.main(TC1.java:11)

but at the top it doesn't have any errors

package test1;

import java.util.Scanner;

public class TC1 {

    public static void main(String[] args){
        double name, age, answer;
        Scanner IN = new Scanner (System.in);
        System.out.println("Whats yor name?");
        name = IN.nextDouble();
        System.out.println("How old are you?");
        age = IN.nextDouble();
        answer = age + name;
        System.out.println(answer);
    }
}

Alberto · Accepted Answer · 2013-09-14 14:04:05Z

1

name is actually a variable of type double. But maybe you are asking for the name which should be of type string.

Change the type of name and use name = IN.nextLine();

answered Sep 14, 2013 at 14:04

Alberto

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3 Comments

user2779262 Over a year ago

i also have another problem that his guy named 19 isn't really helping me since i'm a begginer at this java thing...

user2779262 Over a year ago

link is stackoverflow.com/questions/20111392/…

user2779262 Over a year ago

it would be really helpful

fujy · Accepted Answer · 2013-09-14 14:08:18Z

0

Try this:

Change type of you variables to String instead of double, and use Scanner.next()

public class TC1 {

    public static void main(String[] args){
        String name, age, answer;
        Scanner IN = new Scanner (System.in);
        System.out.println("Whats yor name?");
        name = IN.next();
        System.out.println("How old are you?");
        age = IN.next();
        answer = age + name;
        System.out.println(answer);
    }
}

answered Sep 14, 2013 at 14:08

fujy

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Comments

Atul Yadav · Accepted Answer · 2015-09-30 12:39:54Z

0

This exception will be thrown when you will give non-numeric input.

In your case you have declared name as a double, and I am quite sure that you are entering a non-numeric value in it, say Travis or Lita whatever :)

So either declare name as String and use IN.next() or try entering a numeric value :)

answered Sep 30, 2015 at 12:39

Atul Yadav

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