I am trying to save a sequence of images in visual studio 2008,all with the prefix of "Image". the only differentiating factor should be their number. for example if I am gonna save 10 images then the situation should be
i=1;
while(i<10)
{
cvSaveImage("G:/OpenCV/Results/Imagei.jpg",img2);
i++
//"i" is gonna be different every time
}
so I need to concatenete the integer with the string... looking forward to the answer...
The c++ way (pre-c++11) would be:
#include <sstream>
...
ostringstream convert;
convert << "G:/OpenCV/Results/Image" << i << ".jpg";
cvSaveImage(convert.str().c_str(), img2);
i++;
With C++11:
#include <string>
string filename = "G:/OpenCV/Results/Image" + to_string(i) + ".jpg";
cvSaveImage(filename.c_str(), img2);
edit
A generic and possibly more efficient way of building strings is to use a stringstream:
ostringstream ss;
ss << "G:/OpenCV/Results/Image" << i << ".jpg";
string filename = ss.str();
cvSaveImage(filename.c_str(), img2);
This also works with pre-C++11 compilers.
First of all, if you start with i = 10 and do while( i < 10 ), then your code will save only 9 items. Now to your question,
for( i = 1; i < 11; i++ )
{
std::stringstream imagenum;
imagenum << "G:/OpenCV/Results/Image" << i << ".jpg" ;
cvSaveImage(imagenum.str().c_str(), img2) ;
}
Check example_link
opencv comes with cv::format() [which is probably just a sprintf wrapper, but quite handy, imho]
so, your example could look like:
cv::imwrite( cv::format( "G:/OpenCV/Results/Image%d.jpg", i ), img );
or, if you insist on using the outdated 1.0 api, :
cvSaveImage( cv::format( "G:/OpenCV/Results/Image%d.jpg", i ).c_str(), img );
string imgname="./Image_";
char cbuff[20];
sprintf (cbuff, "%03d", i);
imgname.append(cbuff);
imgname.append(".jpg");
Output:
./Image_001.jpg
./Image_002.jpg
./Image_010.jpg etc.
