use read() to take user input instead of scanf

Question

Im trying to use the read() function to take user input but the only thing I can find in the documentation is regarding reading from files, this is in Linux c language. I also want to use write() do display something to the console.

Does anyone have any idea how this is done?

have a look here stackoverflow.com/questions/9610064/read-stdin-in-c — StoryTeller - Unslander Monica
– StoryTeller - Unslander Monica, Commented Jan 31, 2013 at 21:57
@lxop Probably because it's not always appropriate. (In fact, it does what we want it to do in least cases.) — user529758
– user529758, Commented Jan 31, 2013 at 22:01

user529758 · Accepted Answer · 2013-01-31 21:59:12Z

1

but the only thing I can find in the documentation is regarding reading from files

Don't worry, the standard input is a file.

char buf[128];
read(STDIN_FILENO, buf, sizeof(buf));

I also want to use write() do display something to the console.

Let me not repeat myself.

const char *s = "Hello World!\n";
write(STDOUT_FILENO, s, strlen(s));

answered Jan 31, 2013 at 21:59

user529758

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Comments

pbhd · Accepted Answer · 2013-01-31 22:00:09Z

0

This here should give you an impression how to do it (0 is stdin, 1 is stdout)

#include <unistd.h>
#include <string.h>
int main () {
  char buf[100];
  char *msg="you wrote:";
  while (1) {
    int n;
    n=read (0, buf, sizeof(buf));
    write (1, msg, strlen(msg));
    write (1, buf, n);
  }
}

answered Jan 31, 2013 at 22:00

pbhd

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2 Comments

vonbrand Over a year ago

Be careful, this will wait until the user types 100 characters before read(2) returns.

pbhd Over a year ago

No, it doesn't, it also returns after \n

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