How do I get the name of a running Python script?
I tried os.__file__ but that returns the name of the file where os resides.
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2Duplicate: stackoverflow.com/questions/50499/…S.Lott– S.Lott2009-09-20 11:46:12 +00:00Commented Sep 20, 2009 at 11:46
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stackoverflow.com/q/4152963/2336725 seems to be a better duplicate.Teepeemm– Teepeemm2014-05-12 22:27:14 +00:00Commented May 12, 2014 at 22:27
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6 Answers
>> import os
>> import sys
>> print sys.argv[0]
or if you just want the script and not the full path
>>
>> print os.path.basename(sys.argv[0])
Comments
Use
thisFile = __file__
It's magic!
4 Comments
bos
I get
NameError: name '__file__' is not defined.
Charles Ritchie
Which Python implementation are you using? CPython or something else?
bos
Python 2.7.3. I just ran "python" then
print __file__.
Fred Wu
@bos I don't think you can get it from interactive mode, need to be run as a file.
It depends on what you mean by "a running python script".
__file__ will give you the name of the currently executing file. If that's a module, you'll get where it was imported from e.g. blahblah.pyc
sys.argv[0] will give you the name of the script that is being run, even if called from a module that that script imported.
Please do look up the answers to the earlier question on this topic (see S.Lott's comment on your question).
Comments
sys.argv[0] should give you the name of the script.
Comments
import __main__
print __main__.__file__
This will print the current filename which is running
Comments
sys.path[0]
returns the path of the script that launched the Python interpreter.
If you read this script directly, it will return the path of the script. If the script was imported from another script, it will return the path of that script.
1 Comment
Mawg
I didn't downvote, but just tested. This gave me
K:/code/allRequirementsTests which is the absolute path of the script, minus the extension