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Questions tagged [iid]

iid is an acronym for independent and identically distributed. Many statistical methods assume that the data are iid; that is, that each observation comes from the same distribution and is independent of other observations.

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4 votes
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Given a sample $X_1,\ldots X_n$, how can I test the hypothesis that these are i.i.d. samples from a fixed (unknown) distribution? To add context, assume this is a time series and I want evidence ...
yoyo's user avatar
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3 votes
1 answer
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I am working on a project analyzing olive plantation data, where I aim to simulate the relationship between investment costs (Costs), revenues (...
Barbab's user avatar
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I was working through some econometrics problems, and my professor used the result that the product of iid random variables is iid, but I've seen some posts that this might not always be the case. My ...
rudinable's user avatar
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Take: $X_i , \ i = 1, ... , n $ iid. $\varepsilon_i , \ i = 1, ... ,n$ also iid. $X_i \not \perp \varepsilon_j$ (they are not necessarily independent) Are $X_i \varepsilon_i$ iid ?
Lohey123's user avatar
13 votes
6 answers
2k views

I've read dozens on post on the subject but I cannot figure this out. From what I've gathered, GLMS don't include an error term in their formulation unlike linear models (LM). I was wondering why (or ...
Boussens-Dumon Grégoire's user avatar
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The method-of-moment of $\sigma$ for the following pdf is $$ \text{pdf}(x,\sigma) = \frac{x}{\sigma^2}\exp(-\frac{1}{2}\frac{x^2}{\sigma^2}) $$ $$ E[x] = \int_{0}^{\infty}\frac{x^2}{\sigma^2}\exp(-\...
Andre Kirchner's user avatar
1 vote
1 answer
146 views

I was reading about an approach to Survival Analysis called "First Hitting Time Models" (threshold regression): https://www.jstatsoft.org/article/view/v066i08 , Can Survival Models model the ...
Uk rain troll's user avatar
1 vote
0 answers
93 views

If I have independent and identically distributed random variables $X_1, \dots, X_n$, then are $f(X_1), \dots, f(X_n)$ themselves independent and identically distributed? I think the answer is yes, ...
caitlin's user avatar
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As the title suggests, I would like to find the MGF of the max of iid exponential random variables. Assume $Z=\max(x_{1},...,x_{n})$, where $x_{i}$ is distributed as exponential($\beta$) and has pdf $\...
stats6895997's user avatar
0 votes
1 answer
93 views

Scenario: I have an ordered/indexed sample that supposedly comes from a binomial distribution with fixed probability of success p. (By ordered/indexed I mean that not only I care about the percentage ...
Zmod2Z's user avatar
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1 vote
1 answer
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I am asked to test a hypothesis that a manufacturing line makes p% faulty parts in a month, it's assumed that the p% is independent of the month. My approach is as simple as it gets, take a random ...
abdelrahman esmat's user avatar
3 votes
1 answer
558 views

Suppose I have a time series process $\{X_t\}$ that is strictly stationary in the sense that the joint distribution of $[X_{t_1},...,X_{t_k}]$ and $[X_{t_1+a},...,X_{t_k+a}]$ are the same for any set ...
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1 answer
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Suppose that $X_1, X_2, X_3$ are iid random variables. I have seen this fact many times that $$\mathbb{P}(X_1<X_2<X_3)=\frac{1}{6}$$ but I want to know that why every permutation of $X_1, X_2, ...
user2545's user avatar
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3 votes
1 answer
726 views

Question: Consider a regression model $Y=m(X)+\epsilon$ for which $\epsilon$ is neither independent of $x$ nor identically distributed. How would we go about generating prediction intervals in such a ...
TheFriendlyAsker's user avatar
2 votes
0 answers
40 views

Let $x_0,x_1,...x_n$ be iid (independenta and identically distributed) random variables. Then, $m_0,m_1,...m_n$ be defined as $c-x_0,c-x_1,....c-x_n$, where c is a constant greater than $x_i$ ($i \in \...
Cathy's user avatar
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3 votes
0 answers
74 views

Lots of supervised learning theory is motivated using the IID assumption. Do most of these methods apply equally well if data is only exchangeable, and not IID? Can you provide an example where this ...
capybaralet's user avatar
1 vote
1 answer
384 views

I observe a sequence of r.v. $X_1, X_2, \dots$ where each $X_i$ is a function of the sample size $n$. When $n \rightarrow \infty$ I have the following result: $X_1 \rightarrow^d E_1, X_2 \rightarrow^d ...
Eryna's user avatar
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1 vote
0 answers
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I have built a machine learning model which predicts whether a customer will buy a product or not. The model performs well on cross validation tests. Now, I will deploy it in production to recommend ...
Sanyo Mn's user avatar
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34 views

Consider the following model for aggregate claim amounts $S$: $S=X_{1}+X_{2}+...+X_{N}$ where the $X_{i}$ are independent, identically distributed random variables representing individual claim ...
Pallak Goyal's user avatar
2 votes
0 answers
125 views

This question touches Kolmogorov-Smirnov testing, but asks actually something different. Consider independent random variables $X_1, \dots, X_n$. I want to test the following hypothesis: $$ H_0: X_i\ ...
Albert Paradek's user avatar
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0 answers
435 views

I am generating 10,000 pairs of X and Y such that both X and ...
Kristada673's user avatar
6 votes
1 answer
356 views

Let $S = \frac{X_1 + \cdots + X_n}{n}$ where the $X_i$ are IID Bernoulli distributed with mean $p$, then $E[S] = p$ and $Var(S) = \frac{p(1-p)}{n}$. Now consider the slightly more complex setup where $...
gauss's user avatar
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9 votes
1 answer
533 views

Consider a prediction setting in which we are interested in training a regression or classification function $f$ with inputs $X \in \mathbb{R}^k$ and target $Y$, and assessing its expected ...
Adrian's user avatar
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2 votes
2 answers
245 views

Say that I wish to measure the height of male within the population (so gender=Male is the only factor I am accounting for). Say I collect 100 observations of male height from an elderly population. ...
Michael's user avatar
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1 vote
0 answers
263 views

Let $Y\sim N(\mu, \sigma^2)$ and given sample size $n$, we have an iid sample $\{Y_1, ..., Y_n\}$. We sample $X$ (size $n$) from Bernoulli with probability $\pi$. Denote $Z_i=X_iY_i$. Then, when $X_i=...
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