PHP Parse error: syntax error, unexpected T_PUBLIC [closed]

Question

I am getting this error in this PHP code on line 3, what could be wrong? This code has been taken from php manual user notes by frank at interactinet dot com

<?php

public function myMethod()
{
return 'test';
}

public function myOtherMethod()
{
return null;
}

if($val = $this->myMethod())
{
 // $val might be 1 instead of the expected 'test'
}

if( ($val = $this->myMethod()) )
{
// now $val should be 'test'
}

// or to check for false
if( !($val = $this->myMethod()) )
{
// this will not run since $val = 'test' and equates to true
}

// this is an easy way to assign default value only if a value is not returned:

if( !($val = $this->myOtherMethod()) )
{
$val = 'default'
}

?>

Looks like this is supposed to be part of a class definition. This won't run as is. — deceze
– deceze ♦, Commented Nov 12, 2012 at 9:44
in addition, the code is showcasing bad programming, something you should not do. Why would you want to use the code? — eis
– eis, Commented Nov 12, 2012 at 9:49

RiggsFolly · Accepted Answer · 2019-08-19 15:44:56Z

56

The public keyword is used only when declaring a class method.

Since you're declaring a simple function and not a class you need to remove public from your code.

edited Aug 19, 2019 at 15:44

RiggsFolly

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answered Nov 12, 2012 at 9:44

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3 Comments

expiredninja Over a year ago

what's the difference between a public function in a class and a function out in the open?

Tanner_Gram Over a year ago

You can also hit this error from not closing a bracket & that runs into the next function... It will throw this error on that function. That's what I did. Don't be like me.

Blues Clues Over a year ago

@Tanner_Gram I did what you did so I checked every single braces, and it works

user1607528 · Accepted Answer · 2012-11-12 10:03:25Z

3

You can remove public keyword from your functions, because, you have to define a class in order to declare public, private or protected function

answered Nov 12, 2012 at 10:03

user1607528

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