Extract part of a URL with URL/URI objects

Question

I have a String holding a URL in this format: http://hello.world.com/service/sps/f4c0e810456t And I would like to extract the last part of the URL, i.e. f4c0e810456t.

I can do it with substrings:

    System.out.println(s.substring(s.lastIndexOf("/") + 1, s.length()));

Or regexp however looking for something more elegant using URL/URI objects but couldn't find something.

Any ideas...?

This is what the Java tutorial says about parsing URLs, your requirement does not seem to be part of the list - at least it will deal with weir URLs (queries etc.): docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html — assylias
– assylias, Commented Mar 12, 2012 at 14:35

Michael Laffargue · Accepted Answer · 2012-03-12 14:33:35Z

1

If you can change the URL to "http://hello.world.com/service/sps/?f4c0e810456t" then you could use the getQuery() method (both on URL and URI).

answered Mar 12, 2012 at 14:33

Michael Laffargue

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Andrzej Jozwik · Accepted Answer · 2012-03-12 14:41:11Z

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Example with URL and split (it wrap regular expression for you):

    String address = "http://hello.world.com/service/sps/f4c0e810456t";
    URL url = new URL(address);

     String [] str = url.getPath().split("/");
     String result = str[str.length-1];

answered Mar 12, 2012 at 14:41

Andrzej Jozwik

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1 Comment

Joly Over a year ago

I expected something more "built in" to these Objects that I might be missing but that will do. Thanks!

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