Extract part of a string from a URL - Java Regex

Question

I'm trying to extract a string between '/' and '.' of a URL. For example, I have a URL like "some.com/part1/part2/part3/stringINeed.xyz". I need to extract "stringINeed" from the above URL, the one between last '/' and the '.' nothing else.

So far, I tried the following and it gives an empty output:

import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

class Extract
{
    public static void main (String[] args) throws java.lang.Exception
    {
        String str = "part1/part2/part3/stringINeed.xyz" ;
        Pattern pattern = Pattern.compile("/(.*?).");
        Matcher matcher = pattern.matcher(str);
        if (matcher.find()) {
     System.out.println(matcher.group(1));
        }
    }
}

What is wrong with my code. Can anyone help?

I have a full URL like example.com/part1/part2 and so on.. Part URL's also work as I would eventually end up extracting the URI from the servlet request — Vamsee
– Vamsee, Commented Jul 2, 2014 at 21:45

zx81 · Accepted Answer · 2014-07-02 21:58:45Z

1

Use this regex:

[^/.]+(?=\.[^.]+$)

See demo.

In Java:

Pattern regex = Pattern.compile("[^/.]+(?=\\.[^.]+$)");
Matcher regexMatcher = regex.matcher(subjectString);
if (regexMatcher.find()) {
    ResultString = regexMatcher.group();
}

Explanation

[^/.]+ matches any chars that are not a slash or a dot
The lookahead (?=\.[^.]+) asserts that what follows is a dot followed by non-dots and the end of the string

edited Jul 2, 2014 at 21:58

answered Jul 2, 2014 at 21:46

zx81

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1 Comment

Vamsee Over a year ago

Thaks for your answer Zx81. Worked for me!

zundi · Accepted Answer · 2018-05-31 17:03:13Z

1

Without regex

str.substring(str.lastIndexOf("/"), str.lastIndexOf(".")).replaceAll("/", "");

edited May 31, 2018 at 17:03

zundi

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answered Jun 28, 2017 at 12:27

Vaibs

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