How to create n number of Arrays Dynamically in c#?

Question

First I will ask users "How many names you want to enter?". Once they have entered,I wanted to create that number of arrays. How to create n number of Arrays Dynamically in c#?

Console.WriteLine("How many names you want to Enter?");
int nameCount = Convert.ToInt32(console.Readline());

//I know following code is not possible.But How to make it possible?

for(int i=1;i<=nameCount;i++)
{
  string[] name+i = new string[45];
//what I mean is string[] name1 = new string[45];
  string[] name+i = new string[45];
  string[] name+i = new string[45];
  string[] name+i = new string[45];
  .
  .
  .
}

Dynamically? Use a List<T>. Too much trouble with an array. — user596075
– user596075, Commented Feb 3, 2012 at 3:49
I'm not really sure what you are trying to achieve here, which is probably why you are getting the downvotes. Is this a homework question? Because it reads like it and that could be another reason. There is a tag for homework questions if it is one. Is your problem that you need a single array of users that expands as you add them or something else? — Glenn
– Glenn, Commented Feb 3, 2012 at 3:56
I think OP is just looking for a List<string>, each string instance already can store any number of characters, no other array needed. — BrokenGlass
– BrokenGlass, Commented Feb 3, 2012 at 4:02

KV Prajapati · Accepted Answer · 2012-02-03 03:56:09Z

5

Try List<string[]>

List<string[]> list=new List<string[]>();
for(int i=1;i<5;i++)
 {
   list.add(new string[45]); 
  }

Or

 Dictionary<string,string[]> dictionary;
 dictionary=new Dictionary<string,string[]>();
 for(int i=1;i<=5;i++)
  {
   dictionary.add("string" + i,new string[45]);
  }

edited Feb 3, 2012 at 3:56

answered Feb 3, 2012 at 3:48

KV Prajapati

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1 Comment

VMAtm Over a year ago

Note that List is recreated each time number of items is over some value, so use this constructor, is you can.

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