Why PHP code is not being processed?

Question

I have a PHP page Read.php that echoes the contents of another php file, test.php.test.php contains some php codes but these codes are not processed in Read.php. They are copied as they are.

Read.php

<?php

    $text = 1;
    if ($text == 1){
        $file = file_get_Contents("test.php");
        echo $file;
    }
?>

test.php

<html>
    <body>
        <p>Text
            <?php echo "Manish";  echo $text;>
        </p>
    </body>
</html>

Source code of Read.php

<html>
    <body>
        <p>Text
            <?php echo "Manish";  echo $text;>
        </p>
    </body>
</html>

How do I make this php code process?

RylandAlmanza · Accepted Answer · 2011-10-08 06:40:13Z

2

<?php

    $text = 1;
    if ($text == 1){
        include('test.php');
    }
?>

answered Oct 8, 2011 at 6:40

RylandAlmanza

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Comments

AndrewR · Accepted Answer · 2011-10-08 06:35:16Z

2

Read.php

<?php

$text = 1;
if($text == 1){
  include 'test.php';
}

?>

answered Oct 8, 2011 at 6:35

AndrewR

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Comments

Ignacio Vazquez-Abrams · Accepted Answer · 2011-10-08 06:29:26Z

1

Retrieve it from the web server (http://...) instead of from the filesystem. PHP is only processed if the web server processes it.

answered Oct 8, 2011 at 6:29

Ignacio Vazquez-Abrams

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1 Comment

Amber Over a year ago

Well, technically include()ing or require()ing the file would also result in a similar behavior here.

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