Symfony Forms, formtype label based on a property value of the data object

Question

Is it possible to set the label value of a form type to be a property value that is available in the data object?

My FormType class:

class ShapeFractionType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('value', NumberType::class, [
                'label' => 'name'
            ]);
    }

    public function configureOptions(OptionsResolver $resolver): void
    {
        $resolver->setDefaults([
            'data_class' => ShapeFraction::class,
        ]);
    }
}

The ShapeFraction data class:

class ShapeFraction
{
    public string $name;
    public string $type;
    public float $value;

    // ...
}

Rendering the form:

$shapeFraction = new ShapeFraction('A', 'length', 10);
$form = $formFactory->create(ShapeFractionType::class, $shapeFraction);

// Render using Twig...

The result is a simple form containing a single input with 'name' as label. Is it possible to use the property value of ShapeFraction::$name as the label of the field? Result will become like this: A: <input..>. I would like to achieve this without using the object data directly in Twig or something.

Thanks in advance!

hugo schweitzer · Accepted Answer · 2023-01-05 15:04:00Z

1

You can access the data that you pass to your form using $options['data'].

That means you can do this:

/** @var ShapeFraction $shapeFraction */
$shapeFraction= $options['data'];
$builder->add('value', NumberType::class, [
    'label' => $shapeFraction->name
]);

edited Jan 5, 2023 at 15:04

answered Jan 5, 2023 at 14:43

hugo schweitzer

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1 Comment

sanderbee Over a year ago

Thanks, this solves the issue. My real case only was more complex. The fractions are part of a shape object. I use the CollectionType to render the fractions. In that case, the data index is not available within the $options array. I created a new question for this case: stackoverflow.com/questions/75020710/…

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