Call operator new[] using GDB

Question

How can I call to operator new[] with GDB?

For example I want to allocate 0x40 bytes and print the address : operator new[](0x44u));

How can I do that using GDB ?

When I tried p (void*)operator new[](0x40) I got No symbol "operator" in current context.

Does p (void*)operator new[](0x40) not work?

ssbssa
– ssbssa

2023-01-05 12:39:04 +00:00
Commented Jan 5, 2023 at 12:39 — ssbssa
– ssbssa, Commented Jan 5, 2023 at 12:39
No symbol "operator" in current context.

vtable
– vtable

2023-01-05 13:38:20 +00:00
Commented Jan 5, 2023 at 13:38 — vtable
– vtable, Commented Jan 5, 2023 at 13:38

Employed Russian · Accepted Answer · 2023-01-08 07:00:11Z

1

This worked for me:

(gdb) p 'operator new<TAB>
operator new(unsigned long)
operator new(unsigned long) [clone .cold]
...
operator new[](unsigned long)
operator new[](unsigned long)@got.plt
operator new[](unsigned long)@plt
operator new[](unsigned long, std::align_val_t)
... more choices

(gdb) p 'operator new[](unsigned long)'(0x40)
$1 = (void *) 0x416ee0

answered Jan 8, 2023 at 7:00

Employed Russian

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