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Regex is not my strong suite but I am currently using this regex (\/[\d]+) to get the id from tictok urls.

https://m.tiktok.com/h5/share/usr/6641141594707361797.html
https://m.tiktok.com/v/6749869095467945218.html
https://www.tiktok.com/embed/6567659045795758085
https://www.tiktok.com/share/user/6567659045795758085
https://www.tiktok.com/trending?shareId=6744531482393545985

I get the id from all the links except the one with the shareId=xxxxxxxxxxx. I modified my original regex to the following below and still not getting the id from the link with shareId=xxxxxxxxxxx. Any help will be greatly appreciated.

(?:|shareId=)(\/[\d]+)
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  • 1
    Your regex says "a slash, followed by one or more digits". The last example TikTok URL doesn't have a slash before the digit. Your attempt at fixing it still has this problem. Commented Sep 3, 2022 at 1:25
  • @user2974907 please post an answer to your own question, using ceejayoz's hint. stackoverflow.com/help/self-answer Be sure to mention an online fiddle, perhaps this one: regexr.com/6t871 Commented Sep 3, 2022 at 1:30
  • I used ceejayoz hint and fixed it but now its catching one of the digits in one of the names. See regex. regex101.com/r/ppjnOF/1 Commented Sep 3, 2022 at 1:51

5 Answers 5

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With your shown samples please try following regex. Here is the Online demo for shown regex.

\bhttps?:\/\/(?:m|www)\.tiktok\.com\/.*\b(?:(?:usr|v|embed|user)\/|\?shareId=)(\d+)\b

Explanation: Adding detailed explanation for used regex here.

\bhttps?:\/\/         ##Mentioning word boundary to avoid partial matches for http/https followed by : 2 slashes.
(?:m|www)             ##In a non-capturing group matching m OR www
\.tiktok\.com\/       ##Followed by .tiktok.com
.*\b                  ##Doing greedy match followed by word boundary.
(?:                   ##Starting one non-capturing group here.
  (?:                 ##Starting one more non-capturing group here.
    usr|v|embed|user  ##matching usr OR v OR embed OR user here.
  )                   ##Closing previously opened non-capturing group here.
  \/                  ##Followed by a literal / here.
  |                   ##putting OR condition here.
  \?shareId=          ##matching ?ShareId= here.
)                     ##Closing firstly opened non-capturing group here.
(\d+)                 ##Creating one and only capturing group which has digits in it.
\b                    ##Followed by word boundary here to avoid partial matches.
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@user2974907, could you please do let me know if this solution has worked for you?
1

You can also make the pattern specific for the tiktok urls in the question, and use a capture group for the digits:

https?://(?:m|www)\.tiktok\.com\b\S*?(?:/(?:use?r|v|embed)/|\bshareId=)(\d+)\b

Explanation

  • https?://(?:m|www)\.tiktok\.com\b Match the start of the urls
  • \S*? Match optional non whitespace chars, as few as possible
  • (?:/(?:use?r|v|embed)/|\bshareId=) Match one of /usr/ /user/ /v /embed/ shareId=
  • (\d+) Capture group 1, match 1+ digits
  • \b A word boundary to prevent a partial word match

See a regex demo.

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1

There are working answers given already, but I want to suggest an elegant-looking solution:

([=/][\d]+)

The first set checks for either '=' or '/' symbol. See https://regex101.com/r/9uNJZ1/1

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You could write it as [=/]\d+
0

You can use this regex:

'''(?:\/|shareId=)\d+(?!.*\/)'''g

It matches either a slash / or shareId= followed one or more digits.

It then adds an extra check that there are no more slashes on that line - this way slashes in names won't match.

Regex101 link

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Okay I used the suggestions given and made the adjustments and got the following regex. see solution and link below. Thanks for all the help.

(?:|shareId=^)\d{19}

https://regex101.com/r/OY8B6h/1

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2 Comments

You could write this as \d{19} because shareId=^ will not match
Yeah, @The fourth bird is quite right. You could replace shareId=^ with shareId=ABC, or with DEF -- each of those three is an expression that never appears in the supplied text. The only saving grace is the "match empty string" to the left of the | vbar. There is nothing in that non-matching group that is helping you at all, best to elide it. In general, for any letter X, if you write X^ it is guaranteed to never match, since ^ caret specifically matches at start of string (or start of line).

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