Removing a particular pattern of a text file in python [duplicate]

Question

I have an input file named file1 which contains:

Student 0 : Performed well but can do better. [76.50%]

Student 1 : Brilliant performance. [98.50%]

In this particular file I just want to remove the % part so that it produces output like:

Student 0 : Performed well but can do better.

Student 1 : Brilliant performance.

I tried in this manner:

with open('file1', 'r') as infile, open('file2', 'w') as outfile:
    temp = infile.read().replace("[[0-9]+]", "").replace("%","")
    outfile.write(temp)

But this is only removing the %sign and giving output as:

Student 0 : Performed well but can do better. [76.50]

Student 1 : Brilliant performance. [98.50]

U13-Forward · Accepted Answer · 2021-10-12 04:59:51Z

1

You still need regex:

import re
with open('file1', 'r') as infile, open('file2', 'w') as outfile:
    temp = re.sub("\[[\d+\.%]+\]", "", infile.read())
    outfile.write(temp)

edited Oct 12, 2021 at 4:59

answered Oct 12, 2021 at 4:45

U13-Forward

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4 Comments

Dev Over a year ago

It is giving a warning saying : "FutureWarning: Possible nested set at position 1 temp = re.sub("[[0-9]+]", "", infile.read()).replace("%","")"

U13-Forward Over a year ago

@Dev Check my edit

Dev Over a year ago

Yes, thanks. Now I am getting my desired output but that future warning is still there. Can you help?

U13-Forward Over a year ago

@Dev Check my edit

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