How can I convert from bytes to binary numbers in Python?

Question

So I'm a total Python beginner and I got this byte object:

byte_obj = b'\x45\x10\x00\x4c\xcc\xde\x40\x00\x40\x06\x6c\x80\xc0\xa8\xd9\x17\x8d\x54\xda\x28'

But I have no idea how to put this in a binary number, I only know it's gonna have 32 bits.

Tim Croydon · Accepted Answer · 2021-07-01 13:36:02Z

1

You could try int.from_bytes(...), documented here e.g.:

>>> byte_obj = b'\x45\x10\x00\x4c\xcc\xde\x40\x00\x40\x06\x6c\x80\xc0\xa8\xd9\x17\x8d\x54\xda\x28'

>>> int.from_bytes(byte_obj, byteorder='big')
394277201243797802270421732363840487422965373480

Where byteorder is used to specify whether the input is big- or little-endian (i.e. most or least significant byte first).

(Looks a bit bigger than 32 bits though!)

edited Jul 1, 2021 at 13:36

answered Jul 1, 2021 at 13:01

Tim Croydon

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3 Comments

user16350182 Over a year ago

Thank you I didn't know about that method. What does the byteorder = 'big' do?

Tim Croydon Over a year ago

It's for specifying if the input bytes are 'big-endian' (most significant byte first) or 'little-endian' (LSB first). I'll update answer to include that detail.

Tim Croydon Over a year ago

Hi @user16350182, if the answer solved your problem, it would be great if you could mark it as 'accepted' to help others find it more easily.

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