How can use python request to upload file using graphql?

Question

I have a curl code generated through Insomnia which is working fine. I just can't figure out to replicate It with python request.

curl --request POST \
  --url MY_SERVER_URL \
  --header 'Accept: application/json' \
  --header 'Content-type: multipart/form-data; boundary=---011000010111000001101001' \
  --header 'Authorization:  AUTH_TOKEN' \
  --form 'operations={
  "query": "mutation($file: Upload!, $path: String!, $private: Boolean) { uploadFile(file: $file, path: $path, private: $private) }",
  "variables": {
    "file": null,
    "path": "test",
    "private": false
  }
}' \
  --form 'map={ "0": ["variables.file"] }' \
  --form '0=@E:\Development\Technology\Python\small_utilities\barwis\random-files\files\csvs\above serious.csv'

Thanks

kushal parikh · Accepted Answer · 2021-06-18 11:40:58Z

4

I figured out solution. If any one have same issue here is reference code.

file = open('FILE_PATH', 'rb')
auth_headers = {
  "Authorization": f"Bearer {token}"
}

query = """
  mutation($file: Upload!, $path: String!, $private: Boolean) { 
      uploadFile(file: $file, path: $path, private: $private) 
  }
  """
  
variables = { 
    "file": None,
    "path": 'test',
    "private": True
}  

operations = json.dumps({
  "query": query,
  "variables": variables
})

map = json.dumps({ "0": ["variables.file"] })
  
response = requests.post(graphql_url, data = {
    "operations": operations,
    "map": map
  },
  files = {
    "0" : file
  },
  headers = auth_headers
)

answered Jun 18, 2021 at 11:40

kushal parikh

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Comments

leszek.hanusz · Accepted Answer · 2022-02-25 10:35:24Z

1

Another option would be to use the graphql-python/gql library. It supports uploading files, even with streaming!

transport = AIOHTTPTransport(url='YOUR_URL')
# Or transport = RequestsHTTPTransport(url='YOUR_URL')

client = Client(transport=transport)

query = gql('''
  mutation($file: Upload!) {
    singleUpload(file: $file) {
      id
    }
  }
''')

with open("YOUR_FILE_PATH", "rb") as f:

    params = {"file": f}

    result = client.execute(
        query, variable_values=params, upload_files=True
    )

answered Feb 25, 2022 at 10:35

leszek.hanusz

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