How to define myAnnotationProcessor programmatically in source code?

Question

I'm just new to annotations. I've created a sample annotationProcessor to handle my annotations and currently using command line script "-processor defaultproject.annotations.DefaultProcessor " to use it.

is there any way to set this processor from inside the code?

thanks a lot Moein

McDowell · Accepted Answer · 2011-07-16 09:35:01Z

1

The Processor interface says this about the discovery process:

The tool uses a discovery process to find annotation processors and decide whether or not they should be run. By configuring the tool, the set of potential processors can be controlled. For example, for a JavaCompiler the list of candidate processors to run can be set directly or controlled by a search path used for a service-style lookup. Other tool implementations may have different configuration mechanisms, such as command line options; for details, refer to the particular tool's documentation.

Your best bet for defining the processor in your classpath is to provide a META-INF/services/javax.annotation.processing.Processor file containing the text defaultproject.annotations.DefaultProcessor.

(Assuming your tool chain supports this mechanism. This is ultimately compiler/tool/IDE dependent.)

answered Jul 16, 2011 at 9:35

McDowell

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2 Comments

Moein Over a year ago

So sorry I did try , like this : <code> ArrayList<Processor> processors processors.add(new MyDefaultProcessor()); JavaCompiler compiler = ToolProvider.getSystemJavaCompiler(); StandardJavaFileManager fileManager = compiler.getStandardFileManager(null, null, null); CompilationTask compilationTask = compiler.getTask(null, fileManager, null, null, null, null); compilationTask.setProcessors(processors); compilationTask.call(); </code> But I don't know how to replace parameters currently passed 'null'. Thanks a lot

McDowell Over a year ago

@user847577 - see this developerWorks article by David Biesack on dynamic compilation. If you are still having trouble invoking the API, that should probably be a new question.

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