I am trying to run a script which corrects line breaks in all PHP files. This is how it looks like:
find . -type f -name \*.php -print -exec sed -i '' 's/\r//' {} \;
The errors I get for all files is:
./downloader/lib/Mage/Backup/Exception/SomeFile.php sed: can't read
s/\r//: No such file or directory
Whats the error in the script?
Thanks
The problem is on -i, it depends on the OS you use.
sed -i '' 's/\r//' {}
On macOS, sed expects the file extension to use for the backup file as a separate argument, following -i. An empty string, as you use, tells it to not create a backup file.
On Linux, sed expects the file extension to be joined together with -i in a single argument. For example, -i.bak to append .bak to the file name to generate the name of the backup file or -i to not create a backup file.
Since you get an error that says that the file 's/\r//' does not exist it means that you are using Linux and '' is interpreted as the sed program.
Remove '' and it should work:
sed -i 's/\r//' {}
You can do the following:
find . -type f -name \*.php -print -exec sed -i 's/\r//' {} \;
The issue is sed is expecting sed -i <substitution_pattern> <file>. In your incantation, the '' is interpreted as the substitution pattern, then the 's/\r//' is being interpreted as the file
$ find . -type f -name \*.php -print -exec sed -i 's/\r//' {} \; ./something.php $ find . -type f -name \*.php -print -exec sed -i '' 's/\r//' {} \; ./something.php sed: can't read s/\r//: No such file or directory