I am new to scripting and I have a task which consists of extracting a version from a LOC and save it to $VERSION. The line looks like this:
#define PROJECT_VERSION "21.02"
I have to extract "21.02" and save it in $VERSION, using bash. Right now, I am using the following command:
awk '/PROJECT_VERSION/{print $NF}' common/ESUtils.cpp
but it return more strings. Can you help me?
You can also consider using
awk '$2 == "PROJECT_VERSION"{print $3; exit}' common/ESUtils.cpp
That will find the first record wih Field 2 equal to PROJECT_VERSION and output Field 3 value, and exit right after it without looking further in the input file.
See an online demo:
#!/bin/bash
s='#define PROJECT_VERSION "21.02"
1 PROJECT_VERSION "22.02"'
awk '$2 == "PROJECT_VERSION"{print $3; exit}' <<< "$s"
# => "21.02"
Using sed:
VERSION=$(sed -En '/PROJECT_VERSION/s/(^.*\")([[:digit:]]+\.[[:digit:]]+)(\".*$)/\2/p' project.cpp)
Enable regular expression interpretation with -E and then search for the line with "PROJECT_VERSION". With this line, split the line into 3 sections specified in parenthesis and substitute the line for the second section only, printing the result.
The answer would be:
VERSION=`awk '/PROJECT_VERSION/{print $3F}' project.cpp
awk '/PROJECT_VERSION/{print $NF}' fileshould work for you, what isbut it return more stringsyou are getting in output? Please explain it more.