How to #define function-like macro of the function with variable arguments in C

Question

I have a function declared as:

int func(int a, int b, ...);

Then I want to #define a function-like macro as:

#define TEST(A,B) func(A,B,0)

But the compiler always complains: "error: expected declaration specifiers or '...', before numeric constant".

So, how can I eliminate this error?

It might be because the compiler doesn't know how to express 0 in a vararg since there's no type information to match against. Try (int) 0. — tadman
– tadman, Commented Aug 27, 2020 at 4:16

Raghvendra Rao · Accepted Answer · 2020-08-27 04:25:02Z

1

Make sure the function is defined before the #define statement (could be imported too) so the compiler will the data type of a and b. Or you could also try type defining a and b as (int) a.

answered Aug 27, 2020 at 4:25

Raghvendra Rao

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1 Comment

kenmux Over a year ago

Oops, I know why. there's another declaration int func(int a, int b);, which is the case.

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