How to change str into array in rust

Question

how would I go about changing a str into a array of bytes or chars?

for example:
"1.1.1.1" -> ["1", ".", "1", ".", "1", ".", "1"]

The string is an ip so no usual characters.

I have tried doing try_into() but got

expected array `[u8; 10]`
  found struct `std::slice::Iter<'_, u8>`

Any guidance would be appreciated.

Edit: In my use case I have a struct called Player:

struct Player {
    cards: [i32, 2],
    chips: u32,
    ip: [u8; 10],
    folded: bool,
    hand: u8,
}

And I'd like to set the id to a string that would be received and store it as a array. Ideally the struct would impl copy, so a vec can't be used.

a player being made:

Player {
   cards: [4,5],
   chips: 500,
   ip: "localhost", // how to change this to an array
   folded: false,
   hand: 0,
            }

What do you mean by into an array? Returning an array of variable size is not possible in rust. Would a vec of chars solve your problem? — user1937198
– user1937198, Commented Jun 20, 2020 at 2:28
Is the string hardcoded? Because you can do b"1.1.1.1" to make an array which contains the bytes. Otherwise I'd look into the .chars() method. — Optimistic Peach
– Optimistic Peach, Commented Jun 20, 2020 at 2:50
@user1937198 the str is of fixed length, I have a struct with a field that contains an array, otherwise I'd use a vec. I can't use a vec since it is inside a struct. — Will
– Will, Commented Jun 20, 2020 at 10:48
Does this answer your question? How do I collect into an array? — E_net4
– E_net4, Commented Jun 20, 2020 at 11:09

Kitsu · Accepted Answer · 2020-06-20 06:03:03Z

3

str is a special case for a slice type. And unlike an array it does not have a known size at compile-time (i.e. calculated dynamically during program execution), therefore there is no infallible conversion. But you can manually craft an array and iterate over str to get it bytes:

let s = "1.1.1.1";

let mut your_array = [0u8; 10];

if s.len() != your_array.len() {
    // handle this somehow
}

s.bytes()
    .zip(your_array.iter_mut())
    .for_each(|(b, ptr)| *ptr = b);

answered Jun 20, 2020 at 6:03

Kitsu

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