Generating n number of different files in python

Question

In my code I create a text file of random numbers. But I am wondering if it is possible to generate multiple files, each time with different ranges for the random numbers within a for loop.

I have an idea for how to implement this, but I'm not sure how to call the file I make each time testn, with n being the current value of n. So I would have files: test1, test2 and so on.

My implementation so far is:

numberOfFiles = 5 #set this to the number of files you want to make

for n in range(numberOfFiles):
    newFile = open('testn.txt', 'w') #if possible I want to create a file each time and call it testn, where n is the current value of n.

    x = []

    for i in range(10): #number of lines in each file
        x.append(random.randint(0,60 + (n * 10))

    for val in range(len(x)):
        newFile.write(str(x[val]) + "\n")

    newFile.close()

What is the difference between what I have and what you have suggested @quamrana ? — RishtarCode47
– RishtarCode47, Commented Mar 27, 2020 at 15:08
You can dispense with the newFile.close() and your files are automatically closed, even if there is an exception. — quamrana
– quamrana, Commented Mar 27, 2020 at 15:09

Omroth · Accepted Answer · 2020-03-27 14:46:51Z

4

newFile = open('test' + str(n) + '.txt', 'w')

or in python3.6+:

newfile = open(f'test{n}.txt','w')

answered Mar 27, 2020 at 14:46

Omroth

1,1761 gold badge12 silver badges32 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

cjk · Accepted Answer · 2020-03-27 14:47:15Z

2

This should work:

filename = "test" + str(n) + ".txt"
newFile = open(filename, 'w')

answered Mar 27, 2020 at 14:47

cjk

312 bronze badges

Comments

Shaheer · Accepted Answer · 2020-03-27 14:58:28Z

0

This code will work for you it will create 5 text files each file contain 10 random numbers between range that you define in your code:

import random
numberOfFiles = 5
for n in range(numberOfFiles):
    filename = "test" + str(n) + ".txt"
    newFile = open(filename, 'w')
    x = []
    for i in range(10): #number of lines in each file
        x.append(random.randint(0,60 + (n * 10)))

    for val in range(len(x)):
        newFile.write(str(x[val]) + "\n")
    newFile.close()

answered Mar 27, 2020 at 14:58

Shaheer

1,4133 gold badges13 silver badges29 bronze badges

Collectives™ on Stack Overflow

Generating n number of different files in python

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related